regex - 排除正则表达式匹配中的字符串，以进行 sed 处理

Question

我需要将其匹配为替代命令:

whatever__MATCH_THIS__whateverwhatever__AND_THIS__whateverwhatever

我正在尝试:

sed -e 's/__\(.*\)__/\{{\1}}/g' myfile

但是这是急切匹配__MATCH_THIS__whateverwhatever__AND_THIS__，产生:

whatever{{MATCH_THIS__whateverwhatever__AND_THIS}}whateverwhatever

但我想要:

whatever{{MATCH_THIS}}whateverwhatever{{AND_THIS}}whateverwhatever

如何在匹配部分中指定要排除的字符串？我知道如何排除一个字符(例如[^a])，但不知道如何排除字符串。

Answer 1

GNU sed

sed ':k s/__/{{/;s/__/}}/;tk' file

输入:

whatever__MATCH_THIS__whateverwhatever__AND_THIS__whateverwhatever
blah__XXX_XX__blah_blah_blah__XX_XXX__whateverwhatever

输出:

whatever{{MATCH_THIS}}whateverwhatever{{AND_THIS}}whateverwhatever
blah{{XXX_XX}}blah_blah_blah{{XX_XXX}}whateverwhatever