java - JUnit如何处理DateTimeParseException

Question

如何使用 JUnit 测试“错误输入”？我试图通过向 Flight 对象的第一个参数传递一个无法解析为 LocalTime 类型的值来实例化 Flight 对象。当我这样做时，JUnit testConstructor 方法中的“失败”给出了错误。我应该如何处理这个异常才能顺利通过 JUnit 测试？谢谢

protected Flight(String scheduledTime, String eventType, String identifier) {
    try {
        this.scheduledTime = LocalTime.parse(scheduledTime);
        this.eventType = EventType.valueOf(eventType);
        this.identifier = identifier;
        this.actualTime = null;
        this.runwayUsed = null;
    }
    catch(Exception e) {
        System.out.println(e + " Flight constructor");
    } 

} //end of constructor

下面的 try/catch block 中是给出错误的 JUnit 代码。

@Test
public void testConstructor() {

    Flight f1 = new Flight("00:00", "ARRIVAL", "A001");
    Flight f2 = new Flight("00:00", "DEPARTURE", "D001");

    assertEquals(LocalTime.parse("00:00"), f1.getScheduledTime());
    assertEquals(EventType.ARRIVAL, f1.getEvent());
    assertEquals("A001", f1.getIdent());
    assertEquals(null, f1.getActualTime());
    assertEquals(null, f1.getRunwayUsed());

    assertEquals(LocalTime.parse("00:00"), f2.getScheduledTime());
    assertEquals(EventType.DEPARTURE, f2.getEvent());
    assertEquals("D001", f2.getIdent());
    assertEquals(null, f2.getActualTime());
    assertEquals(null, f2.getRunwayUsed());

    //invalid entry for scheduledTime
    try {
        Flight f3 = new Flight("00:0j", "ARRIVAL", "A001");
        fail("Expected exception");
    } //end of try
    catch(Exception e) {
        System.out.println(e);
    } //end of catch

} 

Answer 1

首先，正如 @binoternary 所指出的，你的构造函数不会在自身之外抛出异常，它只是记录它。其次，要使测试仅在引发特定异常时通过，您需要将此注释添加到测试方法中:

@Test(expected = DateTimeParseException.class) // or any other exception class expected to be thrown
public void testException() {
    Flight f3 = new Flight("00:0j", "ARRIVAL", "A001");
}