python - 如何更改字典的键和值

Question

所以我有以下代码，我想要做的是获取输入元组的每隔一个值，并将其保存到字典中作为 dict.key 和 dict.value 首先设置为 0。之后，我想查看保存的字典，并且每次 dict.key 出现在元组中时，我都想输入计数它位于 dict.value 中。该代码当前给我一个错误。

def movie_awards(results):
    """
    I want to ignore every first value of the tuple
    """
    results = list(results)
    
    answer = {x[1]:0 for x in results}
    
    for x in results:
        answer[x[1]] = answer[x] + 1
    
    print(answer)

result = {("Best Picture", "Parasite"),\
          ("Best Actor", "Joker"),\
          ("Best Actress", "Judy"),\
          ("Best Sound Editing", "Ford v Ferrari"),\
          ("Best Sound Editing", "1917"),\
          ("Best Original Score", "Joker"),\
          ("Best Costume Design", "Little Women"),\
          ("Best Visual Effects", "Little Women"),\
          ("Best Director", "Parasite")}

Answer 1

只需使用 += 添加数字即可:

for x in results:
    answer[x[1]] += 1
    
print(answer)

正在做:

answer[x]

python 正在尝试获取键为 ('Best Original Score', 'Joker') 的 key:value 对。因为它不存在，所以会引发一个关键错误。