java - 将 XML 相等文件(空白除外)与 xmlunit 进行比较会产生差异

Question

使用 xmlunit(版本 2.6.0)比较两个 XML 文件会产生差异，而实际上它们应该被视为相等。

XML 1:

<top><a>one</a><b>two</b></top>

XML 2:

<top>
  <a>one</a>
  <b>two</b>
</top>

Java代码: 源 xmlSource1 = Input.fromFile(xmlFile1).build(); 源 xmlSource2 = Input.fromFile(xmlFile2).build();

DefaultNodeMatcher nodeMatcher = new DefaultNodeMatcher(ElementSelectors.byNameAndText);

Diff d = DiffBuilder.compare(xmlSource1)
            .withNodeMatcher(nodeMatcher)
            .withTest(xmlSource2).build();
    Iterable<Difference> diffList = d.getDifferences();
    Iterator<Difference> iterator = diffList.iterator();
    while(iterator.hasNext()) {
        Difference next = iterator.next();
        log.info("Difference: " + next);
    }

产生此输出:

Difference: Expected child 'top' but was 'null' - comparing <top...> at /top[1] to <NULL> (DIFFERENT)
Difference: Expected child 'null' but was 'top' - comparing <NULL> to <top...> at /top[1] (DIFFERENT)

问题:为什么它们被认为是不同的？如何通过忽略空白差异来进行比较？理想情况下，我希望 d.hasDifferences() 为 false。

Answer 1

只需忽略空格(和注释)并执行检查差异中不包含相似之处(请参阅 checkForSimilar()):

Diff d = DiffBuilder.compare(xmlSource1).withTest(xmlSource2)
 .checkForSimilar()
 .withNodeMatcher(nodeMatcher)
 .ignoreWhitespace()
 .ignoreComments()
 .build();