java - 如何使用 HtmlUnit 显示所有 AJAX 请求

Question

我想获取网页所有网络调用的列表。这是页面的网址

https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc

如果查看 DeveloperConsole->Network，您将看到以下列表

这是我的代码:

public static void main(String[] args) throws IOException {
        final WebClient webClient = configWebClient();
        final List<String> list = new ArrayList<>();
        new WebConnectionWrapper(webClient) {
            @Override
            public WebResponse getResponse(final WebRequest request) throws IOException {
                final WebResponse response = super.getResponse(request);
                list.add(request.getUrl().toString());
                return response;
            }
        };
        webClient.getPage("https://www.upwork.com/ab/find-work/");
        list.forEach(System.out::println); 
    }

    private static WebClient configWebClient() {
        WebClient webClient = new WebClient(BrowserVersion.FIREFOX_60);

        webClient.getOptions().setJavaScriptEnabled(true);
        webClient.waitForBackgroundJavaScriptStartingBefore(5_000);
        webClient.waitForBackgroundJavaScript(3_000);
        webClient.getOptions().setCssEnabled(false);
        webClient.getOptions().setRedirectEnabled(true);
        webClient.getOptions().setUseInsecureSSL(false);
        webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getCookieManager().setCookiesEnabled(true);
        webClient.setAjaxController(new AjaxController());
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getCookieManager().setCookiesEnabled(true);
        return webClient;
    }

这是输出

https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc
https://www.upwork.com/o/jobs/browse/?q=Java
https://www.upwork.com:443/o/jobs/browse/js/328ecc3.js?4af40b2
https://www.googletagmanager.com/gtm.js?id=GTM-5XK7SV
https://client.perimeterx.net/PXSs13U803/main.min.js
https://assets.static-upwork.com/components/11.4.0/core.11.4.0.air2.min.js
https://assets.static-upwork.com/global-components/@latest/ugc.js
https://assets.static-upwork.com/global-components/@latest/ugc/ugc.6jcmqb32.js
https://www.upwork.com:443/static/jsui/JobSearchUI/assets/4af40b2/js/55260a3.js

如您所见，它不包含 xhr 调用。我做错了什么？

Answer 1

您的问题使用两个不同的 URL；希望我用对了

• 正如这里多次提到的； .waitForBackground...方法不是选项，您必须在调用某些 Web 请求后调用它们
• AJAX 中的 A 代表异步； webClient.getPage() 是同步调用，意味着您必须等待所有 javascript 完成

• 使用 HtmlUnit 时调用页面似乎会产生一些 js 错误。也许这会导致无法执行该页面中的所有 javascript 代码(HtmlUnit (Rhino) 仍然不支持一些 javascript 功能；欢迎任何帮助)

  public static void main(String[] args) throws IOException {
      final WebClient webClient = new WebClient(BrowserVersion.FIREFOX_60);
      webClient.getOptions().setThrowExceptionOnScriptError(false);
  
      final List<String> list = new ArrayList<>();
  
      new WebConnectionWrapper(webClient) {
          @Override
          public WebResponse getResponse(final WebRequest request) throws IOException {
              final WebResponse response = super.getResponse(request);
              list.add(request.getHttpMethod() + " " + request.getUrl());
              return response;
          }
      };
  
      webClient.getPage("https://www.upwork.com/o/jobs/browse/?q=Java&sort=renew_time_int%2Bdesc");
      webClient.waitForBackgroundJavaScript(10_000);
      list.forEach(System.out::println); 
  }