java - 根据标签值的变化将 xml 拆分为更小的 XML

Question

<?xml version="1.0" encoding="UTF-16"?>
<ABC>
    <END />
    <Tables>
        <START>
            <row>
                <id>111</id>
                <name>abc</name>
                <deptId>1</deptId>
            </row>
            <row>
                <id>112</id>
                <name>abc1</name>
                <deptId>1</deptId>
            </row>
            <row>
                <id>113</id>
                <name>abc3</name>
                <deptId>1</deptId>
            </row>
            <row>
                <id>222</id>
                <name>def</name>
                <deptId>2</deptId>
            </row>
            <row>
                <id>333</id>
                <name>pqr</name>
                <deptId>2</deptId>
            </row>
            <row>
                <id>444</id>
                <name>xyz</name>
                <deptId>2</deptId>
            </row>
            <row>
                <id>555</id>
                <name>lmn</name>
                <deptId>3</deptId>
            </row>
            <row>
                <id>555</id>
                <name>lmn</name>
                <deptId>3</deptId>
            </row>
        </START>
    </Tables>
</ABC>

我有一个具有上述结构的 xml。我必须根据不同的 deptId 将 xml 分成 3 个 xml。我必须根据标签值的变化将 xml 拆分为更小的 XML。我的元素是 deptId ，其值在某些行后发生了更改。所有具有相同 deptId 的元素都在一个序列中。

所需的输出是:最好将 xml 名称作为部门 ID。

第一个 xml 的名称为 1.xml :

<?xml version="1.0" encoding="UTF-16"?>
<ABC>
    <END />
    <Tables>
        <START>
            <row>
                <id>111</id>
                <name>abc</name>
                <deptId>1</deptId>
            </row>
            <row>
                <id>112</id>
                <name>abc1</name>
                <deptId>1</deptId>
            </row>
            <row>
                <id>113</id>
                <name>abc3</name>
                <deptId>1</deptId>
            </row>
        </START>
    </Tables>
</ABC>

第二个 xml 名称为 2.xml:

<?xml version="1.0" encoding="UTF-16"?>
<ABC>
    <END />
    <Tables>
        <START>
            <row>
                <id>222</id>
                <name>def</name>
                <deptId>2</deptId>
            </row>
            <row>
                <id>333</id>
                <name>pqr</name>
                <deptId>2</deptId>
            </row>
            <row>
                <id>444</id>
                <name>xyz</name>
                <deptId>2</deptId>
            </row>
        </START>
    </Tables>
</ABC>

第三个 xml 名称为 3.xml:

<?xml version="1.0" encoding="UTF-16"?>
<ABC>
    <END />
    <Tables>
        <START>
            <row>
                <id>113</id>
                <name>abc3</name>
                <deptId>1</deptId>
            </row>
        </START>
    </Tables>
</ABC>

我通过引用几个选项尝试使用 StAXSource 选项我尝试过的选项是引用下面的链接

Split xml Split large xml

这是已尝试过的示例代码。

import java.io.File;
import java.io.FileReader;

import javax.xml.stream.XMLInputFactory;
import javax.xml.stream.XMLStreamReader;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stax.StAXSource;
import javax.xml.transform.stream.StreamResult;

public class Demo2 {

public static void main(String[] args) throws Exception {
    XMLInputFactory xif = XMLInputFactory.newInstance();
    XMLStreamReader streamReader = xif.createXMLStreamReader(new FileReader("D://SmallXmltoSplit.xml"));

    streamReader.nextTag(); // Advance to next element
    streamReader.nextTag();
    streamReader.nextTag();
    streamReader.nextTag();
    streamReader.nextTag();
    streamReader.nextTag();

    TransformerFactory tf = TransformerFactory.newInstance();
    Transformer t = tf.newTransformer();
    String deptId = null;
    File file = new File("D://test" + ".xml");
    while (streamReader.hasNext()) {
        if (streamReader.isStartElement()) {
            if (streamReader.getLocalName().equals("deptId")) {
                if (deptId == null) {
                    deptId = streamReader.getElementText();
                    file = new File("D://" + deptId + ".xml");
                    t.transform(new StAXSource(streamReader), new StreamResult(file));
                } else if (deptId != streamReader.getElementText()) {
                    file = new File("D://" + deptId + ".xml");
                    t.transform(new StAXSource(streamReader), new StreamResult(file));
                } 
            }
            t.transform(new StAXSource(streamReader), new StreamResult(file));
        }
        streamReader.next();
    }
}

}

Answer 1

使用 XSLT 2.0 可以更容易地做到这一点:

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform version="2.0">
  <xsl:template match="/">
    <xsl:for-each-group select="//row" group-adjacent="deptId">
      <xsl:result-document href="{current-grouping-key()}.xml">
        <ABC>
         <END />
          <Tables>
           <START>
            <xsl:copy-of select="current-group()"/>
           </START>
          </Tables>
        </ABC>
      </xsl:result-document>
    </xsl:for-each-group>
  </xsl:template>
</xsl:transform>

要从 Java 应用程序运行此程序，您需要下载 Saxon，然后使用以下逻辑调用它:

    Processor proc = new Processor(false);
    XsltCompiler comp = proc.newXsltCompiler();
    XsltExecutable exp = comp.compile(new StreamSource(new File("my-stylesheet.xsl")));
    Serializer out = proc.newSerializer(new File("output.xml"));
    Xslt30Transformer trans = exp.load30();
    trans.applyTemplates(new StreamSource(new File("input.xml"), out);

更多详细信息请参见:http://www.saxonica.com/documentation/index.html#!using-xsl/embedding/s9api-transformation