java - 如何使用枚举中的字符串值作为输入来输出 Java 中该枚举项的其余数据？

Question

我真的想不出如何表达这个问题，但我有一个相当简单的程序，它会要求用户输入元素周期表中的一个元素，然后输出该元素的符号、族和原子质量。目前它只接受元素名称的输入，我试图让它也接受符号的输入，但我不知道该怎么做。例如，此时如果用户输入“Iron”，程序将正确输出，但如果输入“Fe”，则程序将无法工作。我希望“Fe”的输入也能起作用。我对 Java 非常陌生，因此非常感谢有关如何以及为什么的简单解释。

import java.util.Scanner;
public class PeriodicTable {

    public enum Element {
        Hydrogen("H", "Nonmetal", "1.008"),
        Helium("He", "Noble Gas", "4.003"),
        Lithium("Li", "Alkali Metal", "6.941"),
        Beryllium("Be", "Alkaline Earth", "9.012"),
        Boron("B", "Semimetal", "10.811"),
        Carbon("C", "Nonmetal", "12.011"),
        //The rest of the periodic table is here, I just removed it for the sake of this post.

        private String symbol;
        private String group;
        private String weight;

        private Element(String symbol, String group, String weight) {
            this.symbol = symbol;
            this.group = group;
            this.weight = weight;
        }
    }

    static Element cName = null;
    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        System.out.println("Enter the name of an element in the periodic table. ");
        do {
            String input = reader.nextLine();
            try {
                cName = Element.valueOf(input.trim().substring(0, 1).toUpperCase() + input.trim().substring(1).toLowerCase());
            } catch(IllegalArgumentException e) {
                System.out.println("That name is not valid. Please try again. ");
                continue;
            }
            System.out.println("Element: " + cName + " (" + cName.symbol + ")" + "\nGroup: " + cName.group + "\nAtomic Mass: " + cName.weight);
            reader.close();
            break;
        } while (true);
    }
}

Answer 1

集合Element.values()包含枚举类的所有值。
用户提供输入后，循环遍历此集合并检查 symbol 属性以查找元素。

public static void main(String[] args) {
    Scanner reader = new Scanner(System.in);
    boolean found = false;
    do {
        System.out.println("Enter the symbol of an element in the periodic table. ");
        String input = reader.nextLine().trim();

        for (Element e : Element.values()) {
            if (e.symbol.equals(input)) {
                found = true;
                System.out.println("Element: " + e + " (" + e.symbol + ")" + "\nGroup: " + e.group + "\nAtomic Mass: " + e.weight);
            }
        }
        if (!found)
            System.out.println("That symbol is not valid. Please try again. ");
    } while (!found);
    reader.close();
}