java - 家谱，无法解析 child

Question

我对这个任务一无所知。我需要像这样制作家谱

但我无法解决 Main.java 中的 child 问题。对于每个名字，我都必须给 child 写 null 。

这是我的代码:Main.java 。第二个文件:Osoba.java

public class Main {

    public static void main(String[] args) {

        Osoba abraham = new Osoba("Abraham Simpson", null, null, null, null, null, null, null);
        Osoba penelope = new Osoba("Penelope Olsen", null, null, null, null, null, null,null);
        Osoba pan = new Osoba("Pan Bouvier", null, null, null, null, null,null,null);
        Osoba jackie = new Osoba("Jackie Bouvier", null, null, null, null, null,null,null);
        Osoba herb = new Osoba("Herb Powers", abraham, penelope, null, null, null,null,null);
        Osoba homer = new Osoba("Homer Simpson", abraham, penelope, null, null, null,null,null);
        Osoba marge = new Osoba("Marge Simpson", pan, jackie, null, null, null,null,null);
        Osoba selma = new Osoba ("Selma Bouvier", pan, jackie, null, null, null,null,null);
        Osoba bart = new Osoba("Bart Simpson", homer, abraham, penelope,marge, pan,jackie,null);

        bart.sestavRodokmen();
        System.out.println();
        homer.sestavRodokmen();
    }
}



public class Osoba {

    private String name;
    private Osoba father;
    private Osoba dad_grandpa;
    private Osoba dad_grandma;
    private Osoba mother;
    private Osoba mom_grandpa;
    private Osoba mom_grandma;
    private Osoba child;

    public Osoba (String name, Osoba father, Osoba dad_grandpa, Osoba dad_grandma, Osoba mother, Osoba mom_grandpa, Osoba mom_grandma, Osoba child) {
        this.name = name;
        this.father = father;
        this.dad_grandpa = dad_grandpa;
        this.dad_grandma = dad_grandma;
        this.mother = mother;
        this.mom_grandpa = mom_grandpa;
        this.mom_grandma = mom_grandma;
        this.child = child;
    }

    private String rodokmen;

    public void sestavRodokmen () {

        System.out.println("Rodokmen pro osobu: " + name);

        System.out.println("Name: " + name);
        System.out.println("Father: "+ father);
        System.out.println("Grandfather: "+ dad_grandpa);
        System.out.println("Grandmother: "+ dad_grandma);
        System.out.println("Mother: "+ mother);
        System.out.println("Grandfather: "+ mom_grandpa);
        System.out.println("Grandmother: "+ mom_grandma);
        System.out.println("Child: "+ child);

        rodokmen = "";
        System.out.println(rodokmen);
    }

    @Override
    public String toString () {
        String a = "";
        if(mother != null && father != null)
            a += name + "\n" + father + "\n" + mother +"\n" +"\n" + child;
        else
            a += name;

        return a;
    }
}

Answer 1

在 Osaba，只需要直系 parent 和/或直系子女。

在创建新 Osaba 时，仍然无法定义父项或子项。

创作顺序的完全自由将是:

    Osoba abraham = new Osoba("Abraham Simpson");
    Osoba penelope = new Osoba("Penelope Olsen");
    Osoba pan = new Osoba("Pan Bouvier");
    Osoba jackie = new Osoba("Jackie Bouvier");
    Osoba herb = new Osoba("Herb Powers");
    Osoba homer = new Osoba("Homer Simpson");
    Osoba marge = new Osoba("Marge Simpson");
    Osoba selma = new Osoba ("Selma Bouvier");
    Osoba bart = new Osoba("Bart Simpson");

然后使用以下内容创建祖先图:

    herb.setParents(abraham, penelope);
    martha.setParents(null, penelope); // If no father.

现在如果你想检查所有Osaba:是否有人没有 parent ，有人不是他自己的祖先等等，也许你需要一个容器类:

public class Osabas {
    private List<Osaba> persons = new ArrayList<>();

    public Osaba createOsaba(String name) {
        Osaba osaba = new Osaba(name);
        persons.add(osaba);
        return osaba;
    }

    public void drawAncestryDiagram() {
        ...
    }
}

祝你好运!