java - Java输出下划线的逻辑错误

Question

我想编写一个代码，将字符串“thing”中的所有内容都输出为下划线，除了存储在guessChar中的字母之外。目前，该代码是在其自身之上添加的。谁能帮我解决这个逻辑错误？目前，代码给出了一长串下划线。所需的输出是“_e___ _____ E”。

String thing  = "Hello World E";
String phrase = "";
String guessChar = "e";
String phraseCorrectGuessList = "";
boolean l = true;

String alphabet = "abcdefghijklmnopqrstuvwxyz";//String that holds the alphabet that is later used as indexing
phrase = thing.toLowerCase();//String that holds the phrase (lower case)
String hiddenPhrase = "";//String that holds the parts of the phrase that has not yet been unvealed
String phraseOnlyChar = "";//String that holds phrase without all the punctuation
String hiddenPhraseOnlyChar = "";//String that hold the parts of the phrase that has not yet been unvealed without all the punctuation

for (int i = 0; i < thing.length(); i++){
  for (int pos = 0; pos < phrase.length(); pos++){//for loop that checks if there is a space or not
    if (alphabet.indexOf(phrase.charAt(pos)) >= 0){//if there is a letter
      hiddenPhrase = hiddenPhrase + "_ ";//saves to hidden phrase (changes letters to underscrore)
      phraseOnlyChar += phrase.charAt(pos);
    }//end of if
    else{
      hiddenPhrase = hiddenPhrase + phrase.charAt(pos) + " ";//saves area as punctuation
    }//end of else
  }//end of for loop

  if (phrase.indexOf(guessChar) >= 0){//if user enters in a consonant that is in the phrase
    System.out.println("Congratulations, you are correct");//prints out that the user guessed correctly
    phraseCorrectGuessList += guessChar;//adds character to correctly guessed letters string

    System.out.println(hiddenPhrase);//prints the phrase that is hidden
  }

  for (int count = 0; count < phrase.length(); count++){//for loop that goes through every letter in the phrase checks to see if the user inputted character is any character in the phrase
    if (alphabet.indexOf(phrase.charAt(count)) >= 0 && phraseCorrectGuessList.indexOf(phrase.charAt(count)) < 0){//if user inputted character isn't in the phrase
      hiddenPhrase = hiddenPhrase + "_ ";//saves hidden phrase as is
    }//end of if

    else{//if user inputted character is in the phrase
      hiddenPhrase = hiddenPhrase + phrase.charAt(count) + " ";//saves hidden phrase but with all instances of that character revealed
    }//end of else

  }//end of for loop

  for (int index = 0; index < hiddenPhrase.length(); index++){
    if (alphabet.indexOf(hiddenPhrase.charAt(index)) >= 0){
      hiddenPhraseOnlyChar += hiddenPhrase.charAt(index);
    }

  }

}

Answer 1

实际上有一种更简单的方法来做到这一点，

public static void main(String[] args) {
    String thing  = "Hello World E";
    String phrase = "";
    char guessChar = 'e';
    String finalstr = "";
    phrase = thing.toLowerCase();
    for (int i = 0; i < thing.length(); i++){
        char test = phrase.charAt(i);
        if (test == ' ') 
        {
            finalstr += " ";
        }
        else if (test == guessChar)
        {
            finalstr += thing.charAt(i);
        }
        else 
        {
            finalstr += "_";
        }
    }
    System.out.println(finalstr);
}

输出

_e___ _____ E