java - 如何在4秒内定时生成不同的随机数？

Question

我正在尝试编写宾果游戏代码。我想生成 70 个每 4 秒改变一次的随机数。

我创建了一个倒计时器，并通过在倒计时器的芬兰语部分定义一个可运行对象，在 4 秒内创建了一个随机数。但这些随机数可能彼此没有不同。

Handler handler;
Runnable run;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Random random = new Random();
    int i = random.nextInt(70);

    Random random2 = new Random();
    int z = random2.nextInt(70);
    int y =random2.nextInt(70);
    int x =random2.nextInt(70);
    int w =random2.nextInt(70);
    int q =random2.nextInt(70);
    int v =random2.nextInt(70);
    int m =random2.nextInt(70);
    int n =random2.nextInt(70);
    int l =random2.nextInt(70);


    final TextView textView3 = (TextView) findViewById(R.id.textView3);
    final TextView textView4 = (TextView) findViewById(R.id.textView4);
    final TextView textView5 = (TextView) findViewById(R.id.textView5);
    final TextView textView6 = (TextView) findViewById(R.id.textView6);
    final TextView textView7 = (TextView) findViewById(R.id.textView7);
    final TextView textView8 = (TextView) findViewById(R.id.textView8);
    final TextView textView9 = (TextView) findViewById(R.id.textView9);
    final TextView textView10 = (TextView) findViewById(R.id.textView10);



    final TextView textView2 = (TextView) findViewById(R.id.textView2);
    textView2.setText("Lucky number: " + i);

    final int a = Integer.parseInt(textView3.getText().toString());
    final int b = Integer.parseInt(textView4.getText().toString());
    final int c = Integer.parseInt(textView5.getText().toString());
    final int d = Integer.parseInt(textView6.getText().toString());
    final int e = Integer.parseInt(textView7.getText().toString());
    final int f = Integer.parseInt(textView8.getText().toString());
    final int g = Integer.parseInt(textView9.getText().toString());
    final int h = Integer.parseInt(textView10.getText().toString());

    textView9.setText("" + z);
    textView10.setText(" "+ y);
    textView8.setText(" "+ x);
    textView7.setText(" "+ w);
    textView6.setText(" "+ q);
    textView5.setText(" "+ l);
    textView4.setText(" "+ m);
    textView3.setText(" "+ n);


          CountDownTimer ct0 = new CountDownTimer(60000, 1000) {


        @Override
        public void onTick(long millisUntilFinished) {


            TextView textView = (TextView) findViewById(R.id.textView);
            textView.setText("Remaining time: " + millisUntilFinished / 1000);

        }

        @Override
        public void onFinish() {


        }
    }.start();

    CountDownTimer ct1 = new CountDownTimer(4000, 1000) {


        @Override
        public void onTick(long millisUntilFinished) {

        }

        @Override
        public void onFinish() {


            handler = new Handler();
            run = new Runnable() {
                @Override
                public void run() {

                    int[] numbers = new int[70];
                    Random random = new Random();
                    int i = random.nextInt(70);

                    TextView textView2 = (TextView) findViewById(R.id.textView2);
                    textView2.setText("Lucky number: " + i);

                    if ( i == a) {

                        textView3.setText("ok");
                    } else if (i == b) {
                        textView4.setText("ok");
                    } else if (i == c) {

                        textView5.setText("ok");
                    } else if (i == d) {
                        textView6.setText("ok");

                    } else if (i == e) {
                        textView7.setText("ok");
                    } else if(i == f) {
                        textView8.setText("ok");
                    } else if (i == g) {
                        textView9.setText("ok");
                    } else if (i == h) {
                        textView10.setText("ok");
                    }



                    handler.postDelayed(this, 4000);

                }
            };

            handler.post(run);



            }
        }.

        start();

}

在 60 秒内，我想每 4 秒创建 70 个不同的数字，并将这些数字与其他 8 个变量进行匹配。如果您能提供帮助，我将不胜感激。谢谢。

Answer 1

我可以给你一个方法来做到这一点，以避免你所说的:

But these random numbers may not be different from each other.

这是显而易见的，因为你无法控制它。

我想说创建一个 Set<Integer>你的大小是 70，所以你可以通过简单的 for 来填充这个数组循环。

for (int i = 0; i<70; i++) yourSetList.add(i);

然后“模拟”宾果游戏的一个好方法是对列表进行洗牌，因此您可以使用 Collections shuffle

然后你可以像这样生成一个随机数:

Random random = new Random();   
int random = random.nextInt(yourSetList.size()) + 1;

然后使用随机作为索引

yourSetList.get(random);

请确保将其从列表中删除，以避免出现最初的问题

yourSetList.remove(random);