java - 带有常量变量的 For() 循环不打印任何输出

Question

问题是没有发生输出，而不是额外的 println()。这很奇怪，因为在没有静态 SIZE var 的情况下进行此编程，它工作得很好。

public class SlashFigure2
{
    public static final int SIZE = 4;
    public static void main(String[] args)
    {
        for(int i = 1; i <= SIZE; i++)
        {
            for(int j = 1; j <= 2 * i - (2 * SIZE + 2); j++)
            {
                System.out.print("\\");
            }
            
            for(int j = 1; j <= -4 * i + (-4 * SIZE + 2); j++)
            {
                System.out.print("!");
            }
            
            for(int j = 1; j <= 2 * i - (2 * SIZE + 2); j++)
            {
                System.out.print("/");
            }
            
            System.out.println();
        }      
    }  
    
}

如果有人需要它，以下是程序打印的内容:

!!!!!!!!!!!!!!
\\!!!!!!!!!!//
\\\\!!!!!!////
\\\\\\!!//////

编辑:Here's what the site keeps saying is the error

编辑2:该网站是practiceit.csu.washington.edu

问题的措辞如下:

Modify your DollarFigure program from the previous exercise to becomea new program called DollarFigure2 that uses a global constant for thefigure's height. (You may want to make loop tables first.) Theprevious output used a constant height of 7. The outputs below use aconstant size of 3 (left) and 5 (right)

Here are the outputs below they are talking about

(You must solve this problem using only ONE public static finalconstant, not multiple constants; and its value must be used in theway described in this problem.)

Answer 1

只需这样做:

if (i != SIZE) {
    System.out.println();
}

因为在最后一次迭代中i将等于SIZE，并且在这种情况下您想跳过println()。

更新

从注释和图像中，很明显您不应该将 SIZE 定义为常量，显然您应该能够将 n 作为参数传递对于您的程序来说，它不是硬编码值。检查您一直引用的“站点”的规则，应该如何接收输入？