javascript - 按卖家对一系列销售额进行分组，从每个卖家那里获取总数，按总销售额排序

Question

我有一个这样的数组:

[
    {
        "orderId": 1,
        "orderDate": "2021-04-28T08:20:58Z",
        "status": "Confirmed",
        "sellerName": "Chris Gilmour",
        "revenue": 2316.49
    },
    {
        "orderId": 2,
        "orderDate": "2020-12-19T12:30:18Z",
        "status": "Confirmed",
        "sellerName": "Alanna Sumner",
        "revenue": 2928.88
    },
    {
        "orderId": 4,
        "orderDate": "2020-12-24T08:00:09Z",
        "status": "Confirmed",
        "sellerName": "Beth North",
        "revenue": 1550.19
    },
    {
        "orderId": 5,
        "orderDate": "2021-06-06T04:40:48Z",
        "status": "Confirmed",
        "sellerName": "Laura Ponce",
        "revenue": 35.5
    },
    {
        "orderId": 8,
        "orderDate": "2021-08-27T05:13:40Z",
        "status": "Canceled",
        "sellerName": "Blade Newman",
        "revenue": 2957.29
    },
    {
        "orderId": 9,
        "orderDate": "2020-12-26T08:07:57Z",
        "status": "Confirmed",
        "sellerName": "Alanna Sumner",
        "revenue": 2164.75
    },
    {
        "orderId": 10,
        "orderDate": "2021-04-23T18:44:19Z",
        "status": "Confirmed",
        "sellerName": "Blade Newman",
        "revenue": 2287.55
    }
]

我希望新数组是:

[ 
    {
        "sellerName": "Blade Newman",
        "totalRevenue": 5244.84
    },
    {
        "sellerName": "Alanna Sumner",
        "totalRevenue": 5093.63
    },
    { 
        "sellerName": "Chris Gilmour",
        "totalRevenue" : 2316.49
    },
    {
        "sellerName": "Beth North",
        "totalRevenue": 1550.19
    }

]

所以我希望数组按 sellerName 分组，销售量汇总并由总销售额最高的卖家订购。

我试图通过使用 forEachs 和 reduces 来解决这个问题，但我失败了，如果有人能帮助我，那就太好了。

提前致谢。

Answer 1

正如@CarySwoveland在评论中描述的那样，您可以将每个卖家的收入累加到一个对象中，将对象条目转换为数组进行排序，然后根据排序后的值生成一个新对象:

const sales = [{
    "orderId": 1,
    "orderDate": "2021-04-28T08:20:58Z",
    "status": "Confirmed",
    "sellerName": "Chris Gilmour",
    "revenue": 2316.49
  },
  {
    "orderId": 2,
    "orderDate": "2020-12-19T12:30:18Z",
    "status": "Confirmed",
    "sellerName": "Alanna Sumner",
    "revenue": 2928.88
  },
  {
    "orderId": 4,
    "orderDate": "2020-12-24T08:00:09Z",
    "status": "Confirmed",
    "sellerName": "Beth North",
    "revenue": 1550.19
  },
  {
    "orderId": 5,
    "orderDate": "2021-06-06T04:40:48Z",
    "status": "Confirmed",
    "sellerName": "Laura Ponce",
    "revenue": 35.5
  },
  {
    "orderId": 8,
    "orderDate": "2021-08-27T05:13:40Z",
    "status": "Canceled",
    "sellerName": "Blade Newman",
    "revenue": 2957.29
  },
  {
    "orderId": 9,
    "orderDate": "2020-12-26T08:07:57Z",
    "status": "Confirmed",
    "sellerName": "Alanna Sumner",
    "revenue": 2164.75
  },
  {
    "orderId": 10,
    "orderDate": "2021-04-23T18:44:19Z",
    "status": "Confirmed",
    "sellerName": "Blade Newman",
    "revenue": 2287.55
  }
];

let totalsales = sales.reduce((acc, {
  sellerName,
  revenue
}) => {
  acc[sellerName] = (acc[sellerName] || 0) + revenue;
  return acc;
}, {});

totalsales = Object.entries(totalsales)
.sort((a, b) => b[1] - a[1])
.map((v) => ({ sellerName: v[0], totalRevenue: v[1] }))

console.log(totalsales)