windows - 使用正则表达式批量移动文件到新文件夹

Question

我不是开发人员，我只是在寻找获取代码。

我的文件夹:

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...

我只想将文件名为“@2...”的文件和任何文件扩展名移动到“新文件夹”。

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...

我尝试使用正则表达式:(^.+@2.+.$) 请参阅检查 regex101获取完整匹配文本。

我尝试了我的代码但不起作用:

@echo off
setlocal enabledelayedexpansion
for /f %%f in ('dir /b | findstr /r "(^.+@2.+.$)") do (
    md "new folder"
    move "%%~f" "moved folder"
)
Echo done
pause

谁能帮帮我，我错了什么？

更新:感谢@develc(已回答)和@Mofi(已编辑)这很有效，我的文件的完美数量与正则表达式匹配。

md "new folder"
move "*@2x*" "new folder"

另一种方法:这有效，但 0.1% 无法移动，因为无法检测到文件名有注释，例如 example@2x - if comment.png。感谢@Hackoo的回答

@echo off
MD "new folder">nul 2>&1
setlocal enabledelayedexpansion
for /f %%f in ('dir /b *@2*') do (
    move "%%~f" "new folder"
)
Echo done
pause

Answer 1

可以使用这样的东西:

md "new folder"
move "*@2x*" "new folder"

在批处理文件中，*a 表示以 a 结尾的所有内容； b* 表示以 b 开头的所有内容； a*b 表示以 a 开头并以 b 结尾的所有内容； a?b 表示以 a 开头的所有内容，之间有一个字符 a 和 b 并以 b结尾。因此，* 是所有内容的通配符，? 是每个字符的通配符。

参见:MS-DOS and Windows Wildcard Characters在 Microsoft 的文档网站上。