r - 使用 or_glm() 函数调整优势比？

Question

我使用 or_glm() 来计算优势比，使用这个可重现的示例:

    library(oddsratio)
    or_glm(data = data_glm, 
           model = glm(admit ~ gre + gpa + rank, 
                       data = data_glm, 
                       family = "binomial"), 
           incr = list(gre = 1, gpa = 1, rank = 1))

我有两个问题:

1. 如何提取每个优势比的 p 值？
2. 如何获得针对“gpa”和“rank”调整后的“gre”优势比？

Answer 1

我会尝试如下:

library(oddsratio)
library(mfx)

model = glm(admit ~ gre + gpa + rank, 
                   data = data_glm, 
                   family = "binomial")
logitor(admit ~ gre + gpa + rank,data=data_glm)
Call:
logitor(formula = admit ~ gre + gpa + rank, data = data_glm)

Odds Ratio:
      OddsRatio Std. Err.       z     P>|z|    
gre   1.0022670 0.0010965  2.0699 0.0384651 *  
gpa   2.2345448 0.7414651  2.4231 0.0153879 *  
rank2 0.5089310 0.1610714 -2.1342 0.0328288 *  
rank3 0.2617923 0.0903986 -3.8812 0.0001039 ***
rank4 0.2119375 0.0885542 -3.7131 0.0002047 ***
---
Signif. codes:  
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

exp(coef(model))
(Intercept)         gre         gpa       rank2 
  0.0185001   1.0022670   2.2345448   0.5089310 
      rank3       rank4 
  0.2617923   0.2119375 

exp(cbind(OR=coef(model), confint(model)))
Waiting for profiling to be done...
                   OR       2.5 %    97.5 %
(Intercept) 0.0185001 0.001889165 0.1665354
gre         1.0022670 1.000137602 1.0044457
gpa         2.2345448 1.173858216 4.3238349
rank2       0.5089310 0.272289674 0.9448343
rank3       0.2617923 0.131641717 0.5115181
rank4       0.2119375 0.090715546 0.4706961