json - Spring mvc 与 @requestbody 的错误请求

Question

我有一个具有该签名的 Spring MVC 服务:

@RequestMapping(method = RequestMethod.POST, value = "/addUser", consumes = "application/json")
    public @ResponseBody User addUser(@RequestBody User user) {

这在 context.xml 中

<bean id="jacksonMessageConverter"
        class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean>
    <bean
        class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
            <list>
                <ref bean="jacksonMessageConverter" />
            </list>
        </property>
    </bean>

我发出一个 Post 请求，但总是返回 400error->Bad request。我写了一个过滤器来读取请求内容，是这样的:

编辑 json:

{
    "email": "Anchor",
    "latitude": 40.3139461,
    "longitude": -3.8810229,
    "name": "a",
    "online": true,
    "password": "a",
    "deviceRegId": "APA91bGnD1EuqEm9cpoHsenC-HEphQJRniEnhPovK24QkKkLBXrDesSCP6CFlyOKwR1huwSI28Wd-DdN0N8MDKle7myYB7Dznzc3Z11ZOv3jMlJEIegykpnnnYScrElw2czQEa4pKFeQW7BklUsUS-IB15LMqH_Ag"
}

编辑:用户类别

public class User implements Serializable{


@JsonProperty("deviceRegId")
private java.lang.String deviceRegistrationID;
@JsonProperty("email")
private java.lang.String email;
@JsonProperty("latitude")
private java.lang.Double latitude;
@JsonProperty("longitude")
private java.lang.Double longitude;
@JsonProperty("name")
private java.lang.String name;
@JsonProperty("online")
private java.lang.Boolean online;
@JsonProperty("password")
private java.lang.String password;

public User(String deviceRegid) {
    this.deviceRegistrationID = deviceRegid;
    this.online = true;
}

public java.lang.String getDeviceRegistrationID() {
    return deviceRegistrationID;
}

public java.lang.String getEmail() {
    return email;
}

public void setEmail(java.lang.String email) {
    this.email = email;
}

public java.lang.Double getLatitude() {
    return latitude;
}

public void setLatitude(java.lang.Double latitude) {
    this.latitude = latitude;
}

public java.lang.Double getLongitude() {
    return longitude;
}

public void setLongitude(java.lang.Double longitude) {
    this.longitude = longitude;
}

public java.lang.String getName() {
    return name;
}

public void setName(java.lang.String name) {
    this.name = name;
}

public java.lang.Boolean getOnline() {
    return online;
}

public void setOnline(java.lang.Boolean online) {
    this.online = online;
}

/**
 * @return value or {@code null} for none
 */
public java.lang.String getPassword() {
    return password;
}

/**
 * @param password
 *            password or {@code null} for none
 */
public void setPassword(java.lang.String password) {
    this.password = password;
}

有什么问题吗？

Answer 1

请删除参数化构造函数，然后就可以了。 :)

public User(String deviceRegid) {
  this.deviceRegistrationID = deviceRegid;
  this.online = true;
}

因为在数据绑定(bind)时调用默认构造函数。

检查您的 json 数据:

{
  "email": "Anchor",
  "latitude": 40.3139461,
  "longitude": -3.8810229,
  "name": "a",
  "online": true,
  "password": "a",
   "deviceRegId": "APA91bGnD1EuqEm9cpoHsenC-HEphQJRniEnhPovK24QkKkLBXrDesSCP6CFlyOKwR1huwSI28Wd-DdN0N8MDKle7myYB7Dznzc3Z11ZOv3jMlJEIegykpnnnYScrElw2czQEa4pKFeQW7BklUsUS-IB15LMqH_Ag"
}

验证以下事项:

1. JSON 的名称是否与 User 类的字段名称匹配。

2. 同时检查 User 类中相应字段名称 datatype 是否支持 JSON value。

   请尝试一下，我已经多次遇到同样的问题。