javascript - 如何从数组中找到更长的字符串？

Question

我想从此数组中找到更长的字符串:

const myArr = ["第一", "第二", "第三", "第四", "第五", "第六", "七", "第八"]

在此数组中，“第二”、“第四”、“第八”的长度为 6。我想以数组形式返回它们。

const myArr = ["first", "second", "third", "fourth", "fifth", "sixth", "seven", "eighth"]

function longerStrings(arr) {
    let largeStrings = []
    let longerWord = ''
    for (let name of arr) {
        if (name.length > longerWord.length) {
            longerWord = name
            largeStrings.push(longerWord)
        }
    }
    return largeStrings
}
longerStrings(myArr)

预期输出:[“第二”，“第四”，“第八”]

但返回 =["first","second"]

Answer 1

如果您使用过滤器，会更容易:

const myArr = ["first", "second", "third", "fourth", "fifth", "sixth", "seven", "eighth"]
const longest = myArr.reduce((a, b) =>  a.length > b.length ? a : b);
const res = myArr.filter(el => el.length >= longest.length)
console.log(res)

返回:

["second","fourth","eighth"]

或者，正如 Sash 下面提到的，它可以一次性完成，尽管解决方案不那么可读:

let max = 0;
const reducer = myArray.reduce((previous, current) => {
  if (current.length > max) {
    previous = [];
  }
  if (current.length >= max) {
    previous.push(current);
    max = current.length;
  }
  return previous;
}, []);

console.log(reducer);