gpt4 book ai didi

sql-server - SQL Server 中 CASE 的替代方案

转载 作者:行者123 更新时间:2023-12-02 01:24:46 25 4
gpt4 key购买 nike

我有以下两个表:

 CREATE TABLE [dbo].[TAB1](
[COIL_ID] [varchar](25) NOT NULL,
[COIL_DATE] [datetime] NULL,
[GRADE] [float] NULL,
[QUALITY] [float] NULL,
[FURNACE_NUM] [float] NULL,
[FM_GAUGE] [float] NULL,
[FM_WIDTH] [float] NULL,
[FINTEMP_AIM] [float] NULL,
[SLAB_GAUGE] [float] NULL,
[SLAB_WIDTH] [float] NULL,
[SLAB_LENGTH] [float] NULL,
[DO_TEMP] [float] NULL,
[GAP_REFERENCE_PR1_1] [float] NULL,
[GAP_REFERENCE_PR1_2] [float] NULL,
[GAP_REFERENCE_PR1_3] [float] NULL,
[GAP_REFERENCE_PR1_4] [float] NULL,
[GAP_REFERENCE_PR1_5] [float] NULL,
[GAP_REFERENCE_PR1_6] [float] NULL,
[GAP_REFERENCE_PR1_7] [float] NULL,
[GAP_REFERENCE_PR1_8] [float] NULL,
[GAP_REFERENCE_PR1_9] [float] NULL,
[GAP_REFERENCE_PR1_10] [float] NULL,
[GAP_REFERENCE_PR1_11] [float] NULL,
[GAP_REFERENCE_PR1_12] [float] NULL,
[GAP_REFERENCE_PR1_13] [float] NULL,
[GAP_REFERENCE_PR1_14] [float] NULL,
[GAP_REFERENCE_PR1_15] [float] NULL,
[GAP_REFERENCE_PR1_16] [float] NULL,
[GAP_REFERENCE_PR1_17] [float] NULL,
[GAP_REFERENCE_PR1_18] [float] NULL,
[GAP_REFERENCE_PR1_19] [float] NULL,
[GAP_REFERENCE_PR1_20] [float] NULL,
[GAP_REFERENCE_PR1_21] [float] NULL,
[GAP_REFERENCE_PR1_22] [float] NULL,
[GAP_REFERENCE_PR1_23] [float] NULL,
[GAP_REFERENCE_PR1_24] [float] NULL,
[GAP_REFERENCE_PR1_25] [float] NULL
)


CREATE TABLE [dbo].[TAB2](
[COIL_ID] [varchar](25) NOT NULL,
[_SegmentNr] [int] NOT NULL,
[HRM Metal In Mill] [real] NULL,
[HRM Screws Homed] [real] NULL,
[HRM Tracking Current Pass Number] [real] NULL,
[Topmotor_ArmCur] [real] NULL,
[Max_Topmtr_Armcur_pass] [real] NULL,
[Botmotor_ArmCur] [real] NULL,
[Max_Botmtr_Armcur_pass] [real] NULL,
[SPEED] [real] NULL,
[POWER] [real] NULL,
[TEMP] [real] NULL,
[T_Load] [real] NULL,
[D_Load] [real] NULL,
[PosFb] [real] NULL,
[Dif_Pos] [real] NULL,
[Guide_Entry] [real] NULL,
[Guide_Exit] [real] NULL,
[Thread_Achi] [real] NULL
)

在 [dbo].[TAB1] 中会有一行表示 coild-id,在 [dbo].[TAB2] 中会有多行。

我需要的输出如下:

COIL-ID  HRM-Tracking-Current-Pass-Number      GAP
1 1 value of GAP_REFERENCE_PR1_1
1 2 value of GAP_REFERENCE_PR1_2
1 3 value of GAP_REFERENCE_PR1_3

我目前正在使用以下代码:

select a.coil_id Coil_ID, b.[HRM Tracking Current Pass Number] ,
max(case b.[HRM Tracking Current Pass Number]
when 1 THEN a.EXIT_GAUGE_PR1_1
when 2 THEN a.EXIT_GAUGE_PR1_2
when 3 THEN a.EXIT_GAUGE_PR1_3
when 4 THEN a.EXIT_GAUGE_PR1_4
when 5 THEN a.EXIT_GAUGE_PR1_5
when 6 THEN a.EXIT_GAUGE_PR1_6
when 7 THEN a.EXIT_GAUGE_PR1_7
when 8 THEN a.EXIT_GAUGE_PR1_8
when 9 THEN a.EXIT_GAUGE_PR1_9
when 10 THEN a.EXIT_GAUGE_PR1_10
when 11 THEN a.EXIT_GAUGE_PR1_11
when 12 THEN a.EXIT_GAUGE_PR1_12
when 13 THEN a.EXIT_GAUGE_PR1_13
when 14 THEN a.EXIT_GAUGE_PR1_14
when 15 THEN a.EXIT_GAUGE_PR1_15
when 16 THEN a.EXIT_GAUGE_PR1_16
when 17 THEN a.EXIT_GAUGE_PR1_17
when 18 THEN a.EXIT_GAUGE_PR1_18
when 19 THEN a.EXIT_GAUGE_PR1_19
when 20 THEN a.EXIT_GAUGE_PR1_20
when 21 THEN a.EXIT_GAUGE_PR1_21
when 22 THEN a.EXIT_GAUGE_PR1_22
when 23 THEN a.EXIT_GAUGE_PR1_23
when 24 THEN a.EXIT_GAUGE_PR1_24
when 25 THEN a.EXIT_GAUGE_PR1_25
END) as EXIT_GAUGE,

我想知道是否有更有效的方式来编写查询。

在此先感谢您的帮助。

最佳答案

从 SQL Server 2012 开始,有一个 CHOOSE方法:

SELECT CHOOSE ( 3, 'Manager', 'Director', 'Developer', 'Tester' ) AS Result;  

Result
-------------
Developer

所以在你的情况下,你可能会像这样使用它:

SELECT MAX(
CHOOSE(
b.[HRM Tracking Current Pass Number],
a.EXIT_GAUGE_PR1_1,
a.EXIT_GAUGE_PR1_2,
a.EXIT_GAUGE_PR1_3,
...
)
)

关于sql-server - SQL Server 中 CASE 的替代方案,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37759938/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com