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java - 将 java lambda 谓词移植到 scala

转载 作者:行者123 更新时间:2023-12-02 01:22:11 27 4
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如何移植https://github.com/davidmoten/rtree2/blob/master/src/test/java/com/github/davidmoten/rtree2/LatLongExampleTest.java#L55

Iterables.filter(tree
// do the first search using the bounds
.search(bounds),
// refine using the exact distance
entry -> {
Point p = entry.geometry();
Position position = Position.create(p.y(), p.x());
return from.getDistanceToKm(position) < distanceKm;
});

从 Java 到 Scala?我的以下方法失败了:

import com.github.davidmoten.grumpy.core.Position
import com.github.davidmoten.rtree2.{Iterables, RTree}
import com.github.davidmoten.rtree2.geometry.{Geometries, Point}

val sydney = Geometries.point(151.2094, -33.86)
val canberra = Geometries.point(149.1244, -35.3075)
val brisbane = Geometries.point(153.0278, -27.4679)
val bungendore = Geometries.point(149.4500, -35.2500)

var tree = RTree.star.create[String, Point]
tree = tree.add("Sydney", sydney)
tree = tree.add("Brisbane", brisbane)

val distanceKm = 300
val list = Iterables.toList(search(tree, canberra, distanceKm))

def createBounds(from: Position, distanceKm: Double) = { // this calculates a pretty accurate bounding box. Depending on the
// performance you require you wouldn't have to be this accurate because
// accuracy is enforced later
val north = from.predict(distanceKm, 0)
val south = from.predict(distanceKm, 180)
val east = from.predict(distanceKm, 90)
val west = from.predict(distanceKm, 270)
Geometries.rectangle(west.getLon, south.getLat, east.getLon, north.getLat)
}

import com.github.davidmoten.grumpy.core.Position
import com.github.davidmoten.rtree2.RTree

def search[T](tree: RTree[String, Point], lonLat: Point, distanceKm: Double) = { // First we need to calculate an enclosing lat long rectangle for this
// distance then we refine on the exact distance
val from = Position.create(lonLat.y, lonLat.x)
val bounds = createBounds(from, distanceKm)
Iterables.filter(tree.search // do the first search using the bounds
(bounds), // refine using the exact distance
(entry) => {
def foo(entry) = {
val p = entry.geometry
val position = Position.create(p.y, p.x)
from.getDistanceToKm(position) < distanceKm
}

foo(entry)
})
}

因为条目的类型似乎没有明确定义。

最佳答案

tree 的类型为 RTree[String, Point],因此 T=StringS=Point。因此,tree.search(bounds) 的类型为 Iterable[Entry[String, Point]]。因此 entry 的类型为 Entry[String, Point]

尝试

(entry: Entry[String,Point]) => {
def foo(entry: Entry[String,Point]) = {
val p = entry.geometry
val position = Position.create(p.y, p.x)
from.getDistanceToKm(position) < distanceKm
}

foo(entry)
})

在 Scala 2.13.0、rtree2 0.9-RC1、grumpy-core 0.2.4 中测试。

<小时/>

在 2.11 中这应该只是

import scala.compat.java8.FunctionConverters._

((entry: Entry[String,Point]) => {
def foo(entry: Entry[String,Point]) = {
val p = entry.geometry
val position = Position.create(p.y, p.x)
from.getDistanceToKm(position) < distanceKm
}

foo(entry)
}).asJava

libraryDependency += "org.scala-lang.modules"%% "scala-java8-compat"% "0.9.0"

关于java - 将 java lambda 谓词移植到 scala,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57492997/

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