Ansible - 使用用户输入选择变量

Question

我想根据 Ansible 剧本中的用户输入选择特定变量。具体来说，我想在服务器的位置上请求用户输入，然后根据输入执行特定操作。

这是当前的 ansible 剧本:

    - hosts: all
      remote_user: root
      gather_facts: True
      vars:
        loc1: "10.13.1.140"
        loc2: "10.13.1.141"
        loc3: "10.13.1.142"

    vars_prompt:
      - name: location
        prompt: "Location of server?  Input options: loc1/loc2/loc3"
        private: no

    tasks:
      - name: Test connectivity to user selected location
        wait_for: host={{ vars.location }} port=9999 delay=0 timeout=10 state=started

运行剧本时的输出:

[root@ansmgtpr-labc01 cfengine]# ansible-playbook testpoo.yaml -i /tmp/test
SSH password: 
Location of server?  Input options: loc1/loc2/loc3: loc2

PLAY     ***************************************************************************

TASK [setup] *******************************************************************
ok: [hostname.domain.com]

TASK [Test connectivity to user selected location] *****************************
fatal: [hostname.domain.com]: FAILED! => {"changed": false, "elapsed": 10, "failed": true, "msg": "Timeout when waiting for loc2:9999"}

PLAY RECAP *********************************************************************
hostname.domain.com : ok=1    changed=0    unreachable=0    failed=1   

我想知道如何或最佳方式将读取的用户输入位置与在变量部分顶部定义的位置的实际值(IP 地址)链接起来。可能是 eval 还是其他什么？

Answer 1

您的任务正在等待 loc2 ，因此消息 Timeout when waiting for loc2:9999 .

使用 host={{ vars[location] }}反而。

比较以下任务的输出:

tasks:
  - name: Show the value user entered
    debug: var=vars.location

  - name: Use the entered value as an index
    debug: var=vars[location]

结果(缩写):

TASK [Show the value user entered] *********************************************
ok: [localhost] => {
    "vars.location": "loc2"
}

TASK [Use the entered value as an index] ***************************************
ok: [localhost] => {
    "vars[location]": "10.13.1.141"
}