django - 编辑 Django 表单中的现有条目

Question

我的问题类似于how to edit model data using django forms ，但我无法解决它。我想获得一个带有预填字段的表单并允许用户编辑它们。我相信我的问题出在 views.py 文件中，但不幸的是我无法解决它。

模型.py

from django.db import models

class Item(models.Model):
    product = models.CharField(max_length=150)
    quantity = models.DecimalField(max_digits=8, decimal_places=3)
    price = models.DecimalField(max_digits=7, decimal_places=2)
    purchase_date = models.DateTimeField()
    warranty = models.DecimalField(max_digits=4, decimal_places=1)
    comment = models.TextField()

表单.py

from django import forms 
from items.models import Item

class EditItemForm(forms.ModelForm):
    class Meta:
        model = Item
        fields = ('product','quantity', 'price', 'purchase_date', 'warranty', 'comment')

urls.py

from django.conf.urls import patterns, include, url 

urlpatterns = patterns('',
    url(r'^show_all/$', 'items.views.items'),
    url(r'^(?P<item_id>\d+)/$', 'items.views.item'),
    url(r'^edit/(?P<item_id>\d+)/$', 'items.views.edit'),
)

edit.html

<form action="/items/edit/" method="post" class="form horizontal well">{% csrf_token %}
    {{ form.as_p }}
    <imput type="submit" class="btn btn-inverse" value="Aktualizuj">
</form>

views.py

from django.shortcuts import render_to_response
from django.http import HttpResponseRedirect
from items.models import Item
from decimal import Decimal
from django.core.context_processors import csrf
from items.forms import EditItemForm
def edit(request):
    if request.method == 'POST':
        form = EditItemForm(request.POST, instance=request.item)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect('/items/show_all/')

    else:
        form = EditItemForm(instance=item)

    args = {}
    args.update(csrf(request))
    args['form'] = form

    return render_to_response('edit.html', args)

以上代码产生了这条信息:

TypeError at /items/edit/1/

edit() got an unexpected keyword argument 'item_id'

你能帮帮我吗？

Django 1.6、Python 3.4

Answer 1

您想象过一个名为 request.item 的属性。没有这样的事情。您需要通过传递到函数中的 ID 从数据库中获取项目，如 alecxe 所示。

def edit(request, item_id):
    item = Item.objects.get(pk=item_id)
    if request.method == 'POST':
        form = EditItemForm(request.POST, instance=item)