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php - Symfony 2 必须实现 UserProviderInterface

转载 作者:行者123 更新时间:2023-12-02 01:07:12 24 4
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我得到这个错误“必须实现 UserProviderInterface”尝试使用 symfony 登录功能时。我正在引用存储库 * @ORM\Entity(repositoryClass="Login\LogBundle\Entity\Repository\UserRepository") 。有没有人有任何想法。

实体

  <?php
namespace Login\LogBundle\Entity;

use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
/**
* @ORM\Table(name="user")
* @ORM\Entity(repositoryClass="Login\LogBundle\Entity\Repository\UserRepository")
* @ORM\HasLifecycleCallbacks()
*/
class User implements UserInterface, \Serializable
{
/**
* @var integer
*/
private $id;

/**
* @var string
*/
private $password;

/**
* @var string
*/
private $name;

/**
* @var string
*/
private $username;

/**
* @ORM\Column(type="string", length=32)
*/
private $salt;

/**
* @ORM\Column(type="string", length=60, unique=true)
*/
private $email;

/**
* @ORM\Column(name="is_active", type="boolean")
*/
private $isActive;

/**
/**
* @OneToMany(targetEntity="userapidetails", mappedBy="user")
*/
public $userapidetails;

public function __construct()
{
$this->userapidetails = new ArrayCollection();
$this->isActive = true;
$this->salt = md5(uniqid(null, true));
}

public function getUserapidetails() {
return $this->userapidetails;
}

// public function setUserapidetails($userapidetails) {
// $this->userapi=$userapidetails;

// return $this;
// }
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}

/**
* Set password
*
* @param string $password
* @return User
*/
public function setPassword($password)
{
$this->password = $password;

return $this;
}

/**
* Get password
*
* @return string
*/
public function getPassword()
{
return $this->password;
}

/**
* Set name
*
* @param string $name
* @return User
*/
public function setName($name)
{
$this->name = $name;

return $this;
}

/**
* Get name
*
* @return string
*/
public function getName()
{
return $this->name;
}

/**
* Set username
*
* @param string $username
* @return User
*/
public function setUsername($username)
{
$this->username = $username;

return $this;
}

/**
* Get username
*
* @return string
*/
public function getUsername()
{
return $this->username;
}
/**
* @var string
*/
private $isactive;


/**
* Set email
*
* @param string $email
* @return User
*/
public function setEmail($email)
{
$this->email = $email;

return $this;
}

/**
* Get email
*
* @return string
*/
public function getEmail()
{
return $this->email;
}

/**
* Set salt
*
* @param string $salt
* @return User
*/
public function setSalt($salt)
{
$this->salt = $salt;

return $this;
}

/**
* Get salt
*
* @return string
*/
public function getSalt()
{
return $this->salt;
}

/**
* Set isactive
*
* @param string $isactive
* @return User
*/
public function setIsactive($isactive)
{
$this->isactive = $isactive;

return $this;
}

/**
* Get isactive
*
* @return string
*/
public function getIsactive()
{
return $this->isactive;
}




/**
* @inheritDoc
*/
public function getRoles()
{
return array('ROLE_USER');
}

/**
* @inheritDoc
*/
public function eraseCredentials()
{
}

/**
* @see \Serializable::serialize()
*/
public function serialize()
{
return serialize(array(
$this->id,
$this->username,
$this->salt,
$this->password,
));
}

/**
* @see \Serializable::unserialize()
*/
public function unserialize($serialized)
{
list (
$this->id,
$this->username,
$this->salt,
$this->password,
) = unserialize($serialized);
}







}

存储库

      // src/Acme/UserBundle/Entity/UserRepository.php
namespace Login\LogBundle\Entity;

use Doctrine\ORM\EntityRepository;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Core\Exception\UsernameNotFoundException;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Doctrine\ORM\NoResultException;

class UserRepository extends EntityRepository implements UserProviderInterface
{
public function loadUserByUsername($username)
{
$q = $this
->createQueryBuilder('u')
->where('u.username = :username OR u.email = :email')
->setParameter('username', $username)
->setParameter('email', $username)
->getQuery();

try {
// The Query::getSingleResult() method throws an exception
// if there is no record matching the criteria.
$user = $q->getSingleResult();
} catch (NoResultException $e) {
$message = sprintf(
'Unable to find an active admin AcmeUserBundle:User object identified by "%s".',
$username
);
throw new UsernameNotFoundException($message, 0, $e);
}

return $user;
}

public function refreshUser(UserInterface $user)
{
$class = get_class($user);
if (!$this->supportsClass($class)) {
throw new UnsupportedUserException(
sprintf(
'Instances of "%s" are not supported.',
$class
)
);
}

return $this->find($user->getId());
}

public function supportsClass($class)
{
return $this->getEntityName() === $class
|| is_subclass_of($class, $this->getEntityName());
}
}

最佳答案

使用如下内容检查 app/config/security.yml 文件:

# app/config/security.yml
security:
providers:
main:
entity:
class: Acme\UserBundle\Entity\User
property: username

repositoryClass UserRepository 的路径是错误的,也许你的意思是:

@ORM\Entity(repositoryClass="Login\LogBundle\Entity\UserRepository")

因为您使用命名空间 \Login\LogBundle\Entity\UserRepository

关于php - Symfony 2 必须实现 UserProviderInterface,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21185642/

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