python - 确定每天的员工级别

Question

我试图通过每一天来确定员工在组织中的深度。最高层(CEO)是第 1 级，他们的直接下属是第 2 级，等等。

我能够计算无日期，但无法计算每天的员工级别。这是我所做的:

import pandas as pd

# setup df
df = pd.DataFrame({'date': ['3/29/2020', '3/29/2020', '3/29/2020', '3/30/2020', '3/30/2020', '3/30/2020', '3/30/2020'],
                   'empid': [1, 2, 3, 1, 2, 3, 4], 'mgrid': [0, 1, 2, 0, 1, 1, 2]})

# create dictionary
dct = dict(zip(df['empid'].values, df['mgrid'].values))

# function to create employee level
def level(empid):
    top = 1
    while (dct[empid]) != 0:
        top += 1
        empid = dct[empid]
    return top

#apply level
df['level'] = df['empid'].apply(level)

Answer 1

您可以使用 groupby 并每天传递 dct 字典:

def level(empid, dct):
    top = 1
    while (dct[empid]) != 0:
        top += 1
        empid = dct[empid]
    return top

def dflevel(x):
    dct = dict(zip(x['empid'].values, x['mgrid'].values))
    return x['empid'].apply(level, args=[dct])

df['level'] = df.groupby('date').apply(dflevel).values

它给出了预期的结果:

        date  empid  mgrid  level
0  3/29/2020      1      0      1
1  3/29/2020      2      1      2
2  3/29/2020      3      2      3
3  3/30/2020      1      0      1
4  3/30/2020      2      1      2
5  3/30/2020      3      1      2
6  3/30/2020      4      2      3