vba - 使用 VBA 打开 Chrome 并填写表格

Question

我经常使用下面的网站来跟踪往返的航空里程。最近，该网站在 IE 中停止工作，所以我的代码也是如此。由于我在工作计算机上使用它，我无法下载我在搜索中找到的许多其他解决方案，而且我无法在没有经过漫长的过程来获得网站批准的情况下使用其他网站。有没有一种方法可以在 Chrome 中执行相同的任务而无需任何其他下载？

Dim ele As Object

Dim IE As New InternetExplorer
IE.Visible = True

IE.navigate "http://www.distancefromto.net"
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE

'step 1

With IE
.document.getElementsByName("distance")(0).Value = Range("B2").Value
.document.getElementsByName("distance")(1).Value = Range("B3").Value & Range("E3").Value
.document.getElementById("hae").Click

Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE

Application.Wait (Now + TimeValue("0:00:02"))

Dim a As String
a = Trim(.document.getElementById("totaldistancemiles").Value)
Dim aa As Variant
aa = Split(a, " ")
Range("C2").Value = aa(0)

'step 2

.document.getElementsByName("distance")(0).Value = Range("B4").Value & Range("E4").Value
.document.getElementById("hae").Click

Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE

Application.Wait (Now + TimeValue("0:00:02"))

Dim b As String
b = Trim(.document.getElementById("totaldistancemiles").Value)
Dim bb As Variant
bb = Split(b, " ")
Range("C3").Value = bb(0)

'step 3

.document.getElementsByName("distance")(1).Value = Range("B2").Value
.document.getElementById("hae").Click

Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE

Application.Wait (Now + TimeValue("0:00:02"))

Dim c As String
c = Trim(.document.getElementById("totaldistancemiles").Value)
Dim cc As Variant
cc = Split(c, " ")
Range("C4").Value = cc(0)


End With
IE.Quit

任何帮助，即使是明确的“不，这是不可能的”，我们也将不胜感激

谢谢

Answer 1

Chrome:

要使用 Chrome - 不。您需要下载 selenium basic或者使用不同的编程语言，例如 python。

不同站点:

您可以切换到使用不同的网站(请注意，由于网站的原因，您之前的数据可能会有一些细微的差异，但从技术上讲，距离不应该有太大变化!)。我注意到你说这会有问题。冒着听起来像跟踪狂的风险，您使用了 freemaptools之前，所以这可能是一个可以接受的选择？

API:

如果您找到一个提供 API 服务的站点，您或许可以放弃上述所有内容并发出 XMLHTTP request .我看不到您的网站提供 API 服务，否则那将是显而易见的下一个选择。@RahulChalwa 提到“[OP 使用的站点本身使用围绕谷歌地图 API 的包装器:https://maps.googleapis.com/maps/api/js/GeocodeService.Search。用户可以注册 API 并执行 POST 请求]”；所以这可能是前进的方向。主要文档 here .

例如API 站点:个人和小规模使用 API - wheretocredit.com

当前设置调试:

确定 IE 在您当前的设置中不再工作的原因也是可取的，也许可以联系网站开发人员并提出您的问题。

使用 Vincenty's formula 执行计算(如网站所做)或者，像其他网站一样，使用 Haversine 公式:

正弦:

VBA haversine formula

Vicenty 的(包括示例代码):

How to Calculate Distance in Excel

Vicenty 的代码来自 Contextures .我已经归因于但如果这不应该包括在这里我会删除。

'*************************************************************
Private Const PI = 3.14159265358979
Private Const EPSILON As Double = 0.000000000001

Public Function distVincenty(ByVal lat1 As Double, ByVal lon1 As Double, _
    ByVal lat2 As Double, ByVal lon2 As Double) As Double
'INPUTS: Latitude and Longitude of initial and 
'           destination points in decimal format.
'OUTPUT: Distance between the two points in Meters.
'
'======================================
' Calculate geodesic distance (in m) between two points specified by
' latitude/longitude (in numeric [decimal] degrees)
' using Vincenty inverse formula for ellipsoids
'======================================
' Code has been ported by lost_species from www.aliencoffee.co.uk to VBA
' from javascript published at:
' https://www.movable-type.co.uk/scripts/latlong-vincenty.html
' * from: Vincenty inverse formula - T Vincenty, "Direct and Inverse Solutions
' *       of Geodesics on the Ellipsoid with application
' *       of nested equations", Survey Review, vol XXII no 176, 1975
' *       https://www.ngs.noaa.gov/PUBS_LIB/inverse.pdf
'Additional Reference: https://en.wikipedia.org/wiki/Vincenty%27s_formulae
'======================================
' Copyright lost_species 2008 LGPL 
' https://www.fsf.org/licensing/licenses/lgpl.html
'======================================
' Code modifications to prevent "Formula Too Complex" errors
' in Excel (2010) VBA implementation
' provided by Jerry Latham, Microsoft MVP Excel Group, 2005-2011
' July 23 2011
'======================================

  Dim low_a As Double
  Dim low_b As Double
  Dim f As Double
  Dim L As Double
  Dim U1 As Double
  Dim U2 As Double
  Dim sinU1 As Double
  Dim sinU2 As Double
  Dim cosU1 As Double
  Dim cosU2 As Double
  Dim lambda As Double
  Dim lambdaP As Double
  Dim iterLimit As Integer
  Dim sinLambda As Double
  Dim cosLambda As Double
  Dim sinSigma As Double
  Dim cosSigma As Double
  Dim sigma As Double
  Dim sinAlpha As Double
  Dim cosSqAlpha As Double
  Dim cos2SigmaM As Double
  Dim C As Double
  Dim uSq As Double
  Dim upper_A As Double
  Dim upper_B As Double
  Dim deltaSigma As Double
  Dim s As Double ' final result, will be returned rounded to 3 decimals (mm).
'added by JLatham to break up "Too Complex" formulas
'into pieces to properly calculate those formulas as noted below
'and to prevent overflow errors when using
'Excel 2010 x64 on Windows 7 x64 systems
  Dim P1 As Double ' used to calculate a portion of a complex formula
  Dim P2 As Double ' used to calculate a portion of a complex formula
  Dim P3 As Double ' used to calculate a portion of a complex formula

'See https://en.wikipedia.org/wiki/World_Geodetic_System
'for information on various Ellipsoid parameters for other standards.
'low_a and low_b in meters
' === GRS-80 ===
' low_a = 6378137
' low_b = 6356752.314245
' f = 1 / 298.257223563
'
' === Airy 1830 ===  Reported best accuracy for England and Northern Europe.
' low_a = 6377563.396
' low_b = 6356256.910
' f = 1 / 299.3249646
'
' === International 1924 ===
' low_a = 6378388
' low_b = 6356911.946
' f = 1 / 297
'
' === Clarke Model 1880 ===
' low_a = 6378249.145
' low_b = 6356514.86955
' f = 1 / 293.465
'
' === GRS-67 ===
' low_a = 6378160
' low_b = 6356774.719
' f = 1 / 298.247167

'=== WGS-84 Ellipsoid Parameters ===
  low_a = 6378137       ' +/- 2m
  low_b = 6356752.3142
  f = 1 / 298.257223563
'====================================
  L = toRad(lon2 - lon1)
  U1 = Atn((1 - f) * Tan(toRad(lat1)))
  U2 = Atn((1 - f) * Tan(toRad(lat2)))
  sinU1 = Sin(U1)
  cosU1 = Cos(U1)
  sinU2 = Sin(U2)
  cosU2 = Cos(U2)

  lambda = L
  lambdaP = 2 * PI
  iterLimit = 100 ' can be set as low as 20 if desired.

  While (Abs(lambda - lambdaP) > EPSILON) And (iterLimit > 0)
    iterLimit = iterLimit - 1

    sinLambda = Sin(lambda)
    cosLambda = Cos(lambda)
    sinSigma = Sqr(((cosU2 * sinLambda) ^ 2) + _
        ((cosU1 * sinU2 - sinU1 * cosU2 * cosLambda) ^ 2))
    If sinSigma = 0 Then
      distVincenty = 0  'co-incident points
      Exit Function
    End If
    cosSigma = sinU1 * sinU2 + cosU1 * cosU2 * cosLambda
    sigma = Atan2(cosSigma, sinSigma)
    sinAlpha = cosU1 * cosU2 * sinLambda / sinSigma
    cosSqAlpha = 1 - sinAlpha * sinAlpha

    If cosSqAlpha = 0 Then 'check for a divide by zero
      cos2SigmaM = 0 '2 points on the equator
    Else
      cos2SigmaM = cosSigma - 2 * sinU1 * sinU2 / cosSqAlpha
    End If

    C = f / 16 * cosSqAlpha * (4 + f * (4 - 3 * cosSqAlpha))
    lambdaP = lambda

'the original calculation is "Too Complex" for Excel VBA to deal with
'so it is broken into segments to calculate without that issue
'the original implementation to calculate lambda
'lambda = L + (1 - C) * f * sinAlpha * _
  (sigma + C * sinSigma * (cos2SigmaM + C * cosSigma * _
  (-1 + 2 * (cos2SigmaM ^ 2))))
      'calculate portions
    P1 = -1 + 2 * (cos2SigmaM ^ 2)
    P2 = (sigma + C * sinSigma * (cos2SigmaM + C * cosSigma * P1))
    'complete the calculation
    lambda = L + (1 - C) * f * sinAlpha * P2

  Wend

  If iterLimit < 1 Then
    MsgBox "iteration limit has been reached, something didn't work."
    Exit Function
  End If

  uSq = cosSqAlpha * (low_a ^ 2 - low_b ^ 2) / (low_b ^ 2)

'the original calculation is "Too Complex" for Excel VBA to deal with
'so it is broken into segments to calculate without that issue
  'the original implementation to calculate upper_A
  'upper_A = 1 + uSq / 16384 * (4096 + uSq * _
    (-768 + uSq * (320 - 175 * uSq)))
  'calculate one piece of the equation
  P1 = (4096 + uSq * (-768 + uSq * (320 - 175 * uSq)))
  'complete the calculation
  upper_A = 1 + uSq / 16384 * P1

  'oddly enough, upper_B calculates without any issues - JLatham
  upper_B = uSq / 1024 * (256 + uSq * (-128 + uSq * (74 - 47 * uSq)))

'the original calculation is "Too Complex" for Excel VBA to deal with
'so it is broken into segments to calculate without that issue
  'the original implementation to calculate deltaSigma
  'deltaSigma = upper_B * sinSigma * (cos2SigmaM + upper_B / 4 * _
    (cosSigma * (-1 + 2 * cos2SigmaM ^ 2) _
      - upper_B / 6 * cos2SigmaM * (-3 + 4 * sinSigma ^ 2) * _
        (-3 + 4 * cos2SigmaM ^ 2)))
  'calculate pieces of the deltaSigma formula
  'broken into 3 pieces to prevent overflow error that may occur in
  'Excel 2010 64-bit version.
  P1 = (-3 + 4 * sinSigma ^ 2) * (-3 + 4 * cos2SigmaM ^ 2)
  P2 = upper_B * sinSigma
  P3 = (cos2SigmaM + upper_B / 4 * (cosSigma * (-1 + 2 * cos2SigmaM ^ 2) _
    - upper_B / 6 * cos2SigmaM * P1))
  'complete the deltaSigma calculation
  deltaSigma = P2 * P3

  'calculate the distance
  s = low_b * upper_A * (sigma - deltaSigma)
  'round distance to millimeters
  distVincenty = Round(s, 3)

End Function

Function SignIt(Degree_Dec As String) As Double
'Input:   a string representation of a lat or long in the
'         format of 10° 27' 36" S/N  or 10~ 27' 36" E/W
'OUTPUT:  signed decimal value ready to convert to radians
'
  Dim decimalValue As Double
  Dim tempString As String
  tempString = UCase(Trim(Degree_Dec))
  decimalValue = Convert_Decimal(tempString)
  If Right(tempString, 1) = "S" Or Right(tempString, 1) = "W" Then
    decimalValue = decimalValue * -1
  End If
  SignIt = decimalValue
End Function

Function Convert_Degree(Decimal_Deg) As Variant
'source: https://support.microsoft.com/kb/213449
'
'converts a decimal degree representation to deg min sec
'as 10.46 returns 10° 27' 36"
'
  Dim degrees As Variant
  Dim minutes As Variant
  Dim seconds As Variant
  With Application
     'Set degree to Integer of Argument Passed
     degrees = Int(Decimal_Deg)
     'Set minutes to 60 times the number to the right
     'of the decimal for the variable Decimal_Deg
     minutes = (Decimal_Deg - degrees) * 60
     'Set seconds to 60 times the number to the right of the
     'decimal for the variable Minute
     seconds = Format(((minutes - Int(minutes)) * 60), "0")
     'Returns the Result of degree conversion
    '(for example, 10.46 = 10° 27' 36")
     Convert_Degree = " " & degrees & "° " & Int(minutes) & "' " _
         & seconds + Chr(34)
  End With
End Function

Function Convert_Decimal(Degree_Deg As String) As Double
'source: https://support.microsoft.com/kb/213449
   ' Declare the variables to be double precision floating-point.
   ' Converts text angular entry to decimal equivalent, as:
   ' 10° 27' 36" returns 10.46
   ' alternative to ° is permitted: Use ~ instead, as:
   ' 10~ 27' 36" also returns 10.46
   Dim degrees As Double
   Dim minutes As Double
   Dim seconds As Double
   '
   'modification by JLatham
   'allow the user to use the ~ symbol instead of ° to denote degrees
   'since ~ is available from the keyboard and ° has to be entered
   'through [Alt] [0] [1] [7] [6] on the number pad.
   Degree_Deg = Replace(Degree_Deg, "~", "°")

   ' Set degree to value before "°" of Argument Passed.
   degrees = Val(Left(Degree_Deg, InStr(1, Degree_Deg, "°") - 1))
   ' Set minutes to the value between the "°" and the "'"
   ' of the text string for the variable Degree_Deg divided by
   ' 60. The Val function converts the text string to a number.
   minutes = Val(Mid(Degree_Deg, InStr(1, Degree_Deg, "°") + 2, _
             InStr(1, Degree_Deg, "'") - InStr(1, Degree_Deg, "°") - 2)) / 60
   ' Set seconds to the number to the right of "'" that is
   ' converted to a value and then divided by 3600.
   seconds = Val(Mid(Degree_Deg, InStr(1, Degree_Deg, "'") + _
           2, Len(Degree_Deg) - InStr(1, Degree_Deg, "'") - 2)) / 3600
   Convert_Decimal = degrees + minutes + seconds
End Function

Private Function toRad(ByVal degrees As Double) As Double
    toRad = degrees * (PI / 180)
End Function

Private Function Atan2(ByVal X As Double, ByVal Y As Double) As Double
 ' code nicked from:
 ' https://en.wikibooks.org/wiki/Programming:Visual_Basic_Classic
 '  /Simple_Arithmetic#Trigonometrical_Functions
 ' If you re-use this watch out: the x and y have been reversed from typical use.
    If Y > 0 Then
        If X >= Y Then
            Atan2 = Atn(Y / X)
        ElseIf X <= -Y Then
            Atan2 = Atn(Y / X) + PI
        Else
        Atan2 = PI / 2 - Atn(X / Y)
    End If
        Else
            If X >= -Y Then
            Atan2 = Atn(Y / X)
        ElseIf X <= Y Then
            Atan2 = Atn(Y / X) - PI
        Else
            Atan2 = -Atn(X / Y) - PI / 2
        End If
    End If
End Function
'======================================