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predicate - Commercetools - 使用查询谓词过滤集合属性

转载 作者:行者123 更新时间:2023-12-02 00:55:13 24 4
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我想获取在其祖先之间具有特定“id”的祖先的所有类别项目。

这是 返回的类别之一的 JSON获取 来自/categories :

{
"id": "4627f3b0-fe52-4cc6-b03e-3fd72e701342",
"version": 1,
"lastMessageSequenceNumber": 1,
"createdAt": "2019-02-18T13:48:51.677Z",
"lastModifiedAt": "2019-02-18T13:48:51.677Z",
"lastModifiedBy": {
"clientId": "_anonymous"
},
"createdBy": {
"clientId": "_anonymous"
},
"key": "snowboard-gloves",
"name": {
"en": "Snowboard Gloves"
},
"slug": {
"en": "snowboard-gloves"
},
"description": {
"en": "Gloves specifically designed for snowboarding"
},
"ancestors": [
{
"typeId": "category",
"id": "b27086d2-33f2-43c3-aad1-4c01b2b9a886"
}
],
"parent": {
"typeId": "category",
"id": "b27086d2-33f2-43c3-aad1-4c01b2b9a886"
},
"orderHint": "0.000016",
"metaTitle": {
"en": "Snowboard Gloves"
},
"metaDescription": {
"en": "Gloves specifically designed for snowboarding"
},
"assets": []
}

我想调用 /categoriesancestors[x].id = "b27086d2-33f2-43c3-aad1-4c01b2b9a886" 上带有 where 子句的 API但来自 documentation我不明白我应该如何编写查询谓词。

谁能帮我?

最佳答案

查询谓词遵循 json 响应的结构。使用 () 访问嵌套字段括号。

试试这个

ancestors(id = "idb27086d2-33f2-43c3-aad1-4c01b2b9a886")

关于predicate - Commercetools - 使用查询谓词过滤集合属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54751830/

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