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mysql - 从 MySQL 中的 JSON 字符串中提取 key

转载 作者:行者123 更新时间:2023-12-02 00:52:44 25 4
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我的表包含 json 格式的字符串。我需要得到每个键的总和和平均值。

+----+------------------------------------------------------------------------------------+------------+
| id | json_data | subject_id |
+----+------------------------------------------------------------------------------------+------------+
| 1 | {"id": "a", "value": "30"}, {"id": "b", "value": "20"}, {"id": "c", "value": "30"} | 1 |
+----+------------------------------------------------------------------------------------+------------+
| 2 | {"id": "a", "value": "40"}, {"id": "b", "value": "50"}, {"id": "c", "value": "60"} | 1 |
+----+------------------------------------------------------------------------------------+------------+
| 3 | {"id": "a", "value": "20"} | 1 |
+----+------------------------------------------------------------------------------------+------------+

预期结果是

    {"id": "a", "sum": 90, "avg": 30},
{"id": "b", "sum": 70, "avg": 35},
{"id": "c", "sum": 120, "avg": 40}

我试过了

SELECT (
JSON_OBJECT('id', id, 'sum', sum_data, 'avg', avg_data)
) FROM (
SELECT
JSON_EXTRACT(json_data, "$.id") as id,
SUM(JSON_EXTRACT(json_data, "$.sum_data")) as sum_data,
AVG(JSON_EXTRACT(json_data, "$.avg_data")) as avg_data
FROM Details
GROUP BY JSON_EXTRACT(json_data, "$.id")
) as t

但运气不好。我该如何解决这个问题?

最佳答案

输入的json需要更正

create table json_sum (id int primary key auto_increment, json_data json);

insert into json_sum values (0,'[{"id": "a", "value": "30"}, {"id": "b", "value": "20"}, {"id": "c", "value": "30"}]');
insert into json_sum values (0,'[{"id": "a", "value": "40"}, {"id": "b", "value": "50"}, {"id": "c", "value": "60"}]');
insert into json_sum values (0,'[{"id": "a", "value": "20"}]');

select
json_object("id", jt.id, "sum", sum(jt.value), "avg", avg(jt.value))
from json_sum, json_table(json_data, "$[*]" columns (
row_id for ordinality,
id varchar(10) path "$.id",
value varchar(10) path "$.value")
) as jt
group by jt.id

输出:

json_object("id", jt.id, "sum", sum(jt.value), "avg", avg(jt.value))
{"id": "a", "avg": 30.0, "sum": 90.0}
{"id": "b", "avg": 35.0, "sum": 70.0}
{"id": "c", "avg": 45.0, "sum": 90.0}

关于mysql - 从 MySQL 中的 JSON 字符串中提取 key ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56290080/

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