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java - 如何使用java获取hashmap中XML的键值

转载 作者:行者123 更新时间:2023-12-02 00:49:56 25 4
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我遇到一个问题,在获取父键时,我无法根据 XML 的键获取 HashMap 中的值

我正在使用的代码:

public static void main(String[] args) throws IOException {

try {
String XML="<?xml version=\"1.0\" encoding=\"UTF-8\"?>\r\n" +
"<sj0:Msg>\r\n" +
" xmlns:sj0=\"http://fakesite.org/\"\r\n" +
" xmlns:sj1=\"http://fakesite.org/ind\"\r\n" +
" <sj0:Hdr>\r\n" +
" <sj2:Option>CreateTxn</sj2:Option>\r\n" +
" <sj2:ID>172246</sj2:ID>\r\n" +
" <sj2:CountryCode>CR</sj2:CountryCode>\r\n" +
" </sj0:Hdr>\r\n" +
" <sj0:ReqDet>\r\n" +
" <sj0:MReq>\r\n" +
" <sj0:qCore>\r\n" +
" <sj1:Reference>12345678</sj1:Reference>\r\n" +
" <sj1:BrnCode>CLM</sj1:BrnCode>\r\n" +
" <sj1:Source>M1T722</sj1:Source>\r\n" +
" <sj1:TxnLegCount>2</sj1:TxnLegCount>\r\n" +
" </sj0:qCore>\r\n" +
" </sj0:MReq>\r\n" +
" <sj0:LReq>\r\n" +
" <sj0:RCore>\r\n" +
" <sj1:Amt>19.28</sj1:Amt>\r\n" +
" <sj1:Dt>2019-09-04</sj1:Dt>\r\n" +
" <sj1:Date>2019-06-27</sj1:Date>\r\n" +
" </sj0:RCore>\r\n" +
" </sj0:LReq>\r\n" +
" <sj0:LReq>\r\n" +
" <sj0:RCore>\r\n" +
" <sj1:Ind>DC</sj1:Ind>\r\n" +
" <sj1:Currency>US</sj1:Currency>\r\n" +
" <sj1:LAmt>20.28</sj1:LAmt>\r\n" +
" </sj0:RCore>\r\n" +
" </sj0:LReq>\r\n" +
" </sj0:ReqDet>\r\n" +
"</sj0:Msg>";


String XString = XML;
System.out.println(XML);
HashMap<String, String> values = new HashMap<String, String>();
Document xml = convertStringToDocument(XString);

Node user = xml.getFirstChild();

NodeList childs = user.getChildNodes();

Node child;
for (int i = 0; i < childs.getLength(); i++) {
child = childs.item(i);
System.out.println(child.getNodeName());
System.out.println(child.getNodeType());
System.out.println(child.getUserData("Source"));
System.out.println(child.getTextContent());
values.put(child.getNodeName(), child.getTextContent());
}

System.out.println("Source name");
System.out.println(values.toString());
System.out.println(values.get("Source"));

} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}

private static Document convertStringToDocument(String xmlStr) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
try {
builder = factory.newDocumentBuilder();
Document doc = builder.parse(new InputSource(new ByteArrayInputStream(xmlStr.getBytes("UTF-8"))));


return doc;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

输出:

{sj0:ReqDet=

          12345678
CLM
M1T722
2




19.28
2019-09-04
2019-06-27




DC
US
20.28

, #text= , sj0:Hdr= CreateTxn 172246 CR }

我需要在 haspmap 键中添加 Source,而不是 ReqDet。我在遍历 XML 时遇到问题。知道我哪里出错了,还请解释一下如何获取其他键值的值,即 RCore 父键的 Ind 键。

如果这个库有问题,我可以使用任何其他方法或库来完成此任务

最佳答案

下面的代码行有 "*" 这意味着它将从 XML 中选择所有节点/键值

NodeList nodeList = doc.getElementsByTagName("*");

下面是适合我的完整代码:

public static void main(String[] args) throws IOException {
String XML="YOUR XML";

HashMap<String, String> values =convertStringToDocument(XML);
System.out.println("values = "+values.get("sj1:Source"));
}

public static HashMap<String, String> convertStringToDocument(String xmlStr) {
HashMap<String, String> values = new HashMap<String, String>();
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
try {
builder = factory.newDocumentBuilder();
EntityResolver resolver = new EntityResolver() {
public InputSource resolveEntity(String publicId, String systemId) {
String empty = "";
ByteArrayInputStream bais = new ByteArrayInputStream(empty.getBytes());
System.out.println("resolveEntity:" + publicId + "|" + systemId);
return new InputSource(bais);
}
};
builder.setEntityResolver(resolver);
Document doc = builder.parse(new InputSource(new ByteArrayInputStream(xmlStr.getBytes("UTF-8"))));
NodeList nodeList = doc.getElementsByTagName("*");
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
values.put(node.getNodeName(), node.getTextContent());
}
}

return values;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

关于java - 如何使用java获取hashmap中XML的键值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57868171/

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