php - url中参数为空laravel如何处理

Question

我有一个路线-

/first/second/{param}, 'IndexController@index'

在 Controller 中

public function index($param)
{
    $param = trim($param);
    if($param == "")
    {
        redirect()->back();
    }
}

我试图处理它但失败了。每当我发送 /first/second/ 时，如果出现 RouteCollection 错误。我该如何控制它？

Answer 1

请花点时间稍微阅读一下文档:Optional Parameters

Occasionally you may need to specify a route parameter, but make the presence of that route parameter optional. You may do so by placing a ? mark after the parameter name. Make sure to give the route's corresponding variable a default value:

Route::get('user/{name?}', function ($name = null) {
    return $name;
});

Route::get('user/{name?}', function ($name = 'John') {
    return $name;
});

---

因此，在您的情况下，路线将是:

/first/second/{param?}, 'IndexController@index'

在 Controller 中

public function index($param ='')