Java Switch语句: creating a calculator error

Question

我想知道是否有人能看出我的代码有什么问题。它可以工作，只是程序不承认我的 switch 语句 - 我搜索了很多问题，但由于我是新手，我显然错过了一些东西。

import java.util.Scanner;
class Calmlr1 {
    public static void main(String[]args) {
        Scanner input = new Scanner(System.in);
        String anotherOption = "y", operatorOpt= "a";
        int no1=0, no2=0;
        double result= 0;
        System.out.println ("Welcome to the online calculator! Let's begin...");
        while (anotherOption.equalsIgnoreCase ("y")) {
            System.out.println ("Please enter your 1st number: ");
            no1 = input.nextInt();
            System.out.println ("Please confirm your operator:\n1 = +\n2 = - \n3 = *\n4 = /");
            operatorOpt = input.next ();
            System.out.println ("Please enter your 2nd number: ");
            no2 = input.nextInt();

            switch(no1) {
              case 1:
                result=no1+no2;
                break;
              case 2:
                result=no1-no2;
                break;
              case 3:
                result=no1*no2;
                break;
              case 4:
                result=no1/no2; 
              default: 
                result = 0 ;
                break;
            }
            System.out.println("Your total calculation is: "+result);
            System.out.println("Would you like to do another sum? y/n ");
            anotherOption=input.next();
        }
    }
}

Answer 1

您应该使用switch(operatorOpt)。现在您正在接通第一个号码。

您还需要更改:

intoperatorOpt=0;

operatorOpt = input.nextInt();

也就是说，如果您想保持 switch 语句相同。另请参阅@Daniel Imms 的回答以获取其他错误修复。