java - 如何从下面的编码中返回 url 列表

Question

如标题所示，如何返回(a href)引用下的网址列表并将其显示在文本文件中？下面的代码返回 html 形式的网站。

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;

public class Main {
    public static void main(String[] args)  {
        try {
            URL my_url = new URL("http://www.placeofjo.blogspot.com/");
            BufferedReader br = new BufferedReader(
               new InputStreamReader(my_url.openStream()));
            String strTemp = "";
            while(null != (strTemp = br.readLine())){
                System.out.println(strTemp);
            }
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }
}

Answer 1

您听起来像是想要使用 HTML 解析库，例如 HtmlUnit ，而不是陷入自己解析 HTML 的麻烦中。 HtmlUnit 代码将非常简单:

final WebClient webClient = new WebClient();
webClient.setJavaScriptEnabled(false);
final HtmlPage page = webClient.getPage("http://www.placeofjo.blogspot.com/");

//  Then iterate through
for (DomElement element : page.getElementsByTagName("a")){
    String link = ((HtmlAnchor)element).getHrefAttribute();
    System.out.println(link);
}

给出输出:

http://www.twitter.com/jozefinfin/
http://www.facebook.com/jozefinfin/
http://placeofjo.blogspot.com/2008_08_01_archive.html
... etc etc
http://placeofjo.blogspot.com/2011_02_01_archive.html
http://endlessdance.blogspot.com
http://blogskins.com/me/aaaaaa
http://weheartit.com