c# - 如何在 wpf 中使用简单的 wifi 连接到 wifi？

Question

我正在尝试使用 simplewifi 连接到 wifi。目前，我尝试过:

Wifi wifi = new Wifi();

// get list of access points
IEnumerable<AccessPoint> accessPoints = wifi.GetAccessPoints();

// for each access point from the list
foreach (AccessPoint ap in accessPoints)
{
    Console.WriteLine("ap: {0}\r\n", ap.Name);
    //check if SSID is desired
    if (ap.Name.StartsWith("z"))
    {
        //verify connection to desired SSID
        Console.WriteLine("connected: {0}, password needed: {1}, has profile: {2}\r\n", ap.Name, ap.IsConnected, ap.HasProfile);
        if (!ap.IsConnected)
        {
            //connect if not connected
            Console.WriteLine("\r\n{0}\r\n", ap.ToString());
            Console.WriteLine("Trying to connect..\r\n");

            AuthRequest authRequest = new AuthRequest(ap);
            authRequest.Password = "123456789";
            var x=ap.Connect(authRequest);

        }
    }
}

如果我有像这样硬编码的密码，我就不能传递密码

var password="abc123"

如何传递密码并连接？

此外，connect 方法总是返回 false，即使我必须在没有密码的情况下连接到 wifi。

Answer 1

你需要设置authRequest.Password = "yourpassword";

在你的 ap.connect(authRequest); 之前

添加来自 https://github.com/DigiExam/simplewifi 的以下 console.write()

放在文件的顶部

using SimpleWifi;

然后在你的函数中

// Wifi object
Wifi wifi = new Wifi();

// get list of access points
IEnumerable<AccessPoint> accessPoints = wifi.GetAccessPoints();

    // for each access point from list
foreach (AccessPoint ap in accessPoints){
    Console.WriteLine("ap: {0}\r\n", ap.Name);
    //check if SSID is desired
    if (ap.Name.StartsWith("ardrone_")){
        //verify connection to desired SSID
        Console.WriteLine("connected: {0}, password needed: {1}, has profile: {2}\r\n", ap.Name, ap.IsConnected, ap.HasProfile);
        if (!ap.IsConnected){
            //connect if not connected
            Console.WriteLine("\r\n{0}\r\n", ap.ToString());
            Console.WriteLine("Trying to connect..\r\n");
            AuthRequest authRequest = new AuthRequest(ap);
            ap.Connect(authRequest);
        }
    }
}