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django - 在 django 中上传 csv 时,迭代器应该返回字符串,而不是字节(您是否以文本模式打开文件?)

转载 作者:行者123 更新时间:2023-12-02 00:35:46 25 4
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我想上传 csv 文件并存储在数据库中。当我单击提交按钮时,出现以下错误

Environment:


Request Method: POST
Request URL: http://localhost:8000/csv

Django Version: 1.9
Python Version: 3.4.3
Installed Applications:
['django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.gis',
'django.contrib.admindocs',
'world',
'pft',
'wms',
'djgeojson',
'html5',
'geoexplorer']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback:

File "C:\Python34\lib\site-packages\django\core\handlers\base.py" in get_response
149. response = self.process_exception_by_middleware(e, request)

File "C:\Python34\lib\site-packages\django\core\handlers\base.py" in get_response
147. response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "C:\Python34\lib\site-packages\django\contrib\auth\decorators.py" in _wrapped_view
23. return view_func(request, *args, **kwargs)

File "C:\Python34\Lib\site-packages\django\bin\geodjango\pft\views.py" in add_multiple_accounts
95. csv_result, rows_error = utils.handle_uploaded_file(file, utils.account_valid_fields, utils.create_account_in_db)

File "C:\Python34\Lib\site-packages\django\bin\geodjango\pft\utils.py" in handle_uploaded_file
24. if not valid_fields_method(data.fieldnames):

File "C:\Python34\lib\csv.py" in fieldnames
96. self._fieldnames = next(self.reader)

Exception Type: Error at /csv
Exception Value: iterator should return strings, not bytes (did you open the file in text mode?)

我的句柄文件上传函数在下面-utils.py

def handle_uploaded_file(file, valid_fields_method, record_creation_function):
file.seek(0)
sniffdialect = csv.reader(codecs.iterdecode(file, 'utf-8')
file.seek(0)
data = csv.DictReader(file, dialect=sniffdialect)

if not valid_fields_method(data.fieldnames):
return False, -1

result, rows_error = record_creation_function(data)

return result, rows_error

我正在使用 django 1.9 和 python 3.4。请帮忙 !这两天我很挣扎。

最佳答案

TL;博士:

更改此:

file.seek(0)
sniffdialect = csv.reader(codecs.iterdecode(file, 'utf-8')
file.seek(0)
data = csv.DictReader(file, dialect=sniffdialect)

对此:

file.seek(0)
data = csv.DictReader(codecs.iterdecode(file, 'utf-8'))

(顺便说一句,我会检查是否确实需要 seek(0) 。)

<小时/>

说明:

您已经了解您需要解码文件中的内容,这是正确的。但是,为此,您使用的是方言,这是错误的。

dialect 不适用于此类内容。另外,它应该是通过 csv.register_dialect() 注册的名称,而不是任意迭代器。但无论如何,方言在这里帮不了你。

相反,您应该将解码后的流直接传递给 DictReader

关于django - 在 django 中上传 csv 时,迭代器应该返回字符串,而不是字节(您是否以文本模式打开文件?),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34589267/

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