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java - 二分/顺序搜索

转载 作者:行者123 更新时间:2023-12-02 00:34:55 26 4
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我正在尝试编写一个程序,在名为 items 的数组中进行顺序搜索和二分搜索,该数组具有 10000 个已排序的随机 int 值。第二个名为 targets 的数组加载了 1000 个 int 值(500 个来自 items 数组的值和 500 个不在 items 数组)。

基本上,搜索需要遍历 items 数组来查找 targets 数组中的 int 值。这是我的代码:

  import java.util.*;

// Loads two arrays with integers
// Searches the arrays using sequential search and binary search
// Compares the time for each search

public class Searches {

private int items[], targets[];

public Searches() {

this.items = new int[10000];
this.targets = new int[1000];
}

public void loadItemsAndTargets(){

int nextValue = 100;
int index = 0;

Random generator = new Random(1);

items[0] = nextValue;

/* load the items array with items to be searched through */

for (index = 1; index < items.length; index++){
nextValue = nextValue + generator.nextInt(100);
items[index]= nextValue;
}

/* load the targets array with target values that will be searched for within
* array items, and target values that are not within array items
*/

index = 0;

while (index < targets.length){
targets[index] = items[index*10];
targets[index+1] = generator.nextInt(100);
index = index + 2;
}
}

public int sequentialSearch(int target) {
/* Using the sequential search algorithm, search the items array for the target value passed
* If found, return the index in the items array, otherwise return -1
*/
this.loadItemsAndTargets();

int key = target;
int index;

boolean found = false;

index = 0;
while ((!found) && (index < items.length))
if (key == target)
found = true;
else
index = index + 1;

if (!found)
index = -1;
return index;
}

public int binarySearch(int target){
/* Using the binary search algorithm, search the items array for the target value passed
* If found, return the index in the items array, otherwise return -1
*/
this.loadItemsAndTargets();


target = targets.length;
int key = target;
boolean found = false;
int guess = 0;
int low = 0;
int high = items.length - 1;
while ((!found) && (low < high)) {
guess = (high+low)/2;
if (key == items[guess])
found = true;
else if (key < items[guess])
high = guess - 1;
else
low = guess + 1;

if (!found)
return - 1;
}

return guess;
}
public static void main(String[] args) {
int index = 0;
Searches searcher = new Searches();
searcher.loadItemsAndTargets();

/* call the method that searches array items
* for each of the values in array targets
* using the sequential search algorithm
* print the approximate elapsed time in milliseconds
* For the FIRST FIVE searches print out the index
* where target value was found or print -1 if it was not found
*/


long startTimeSequential;
startTimeSequential = System.currentTimeMillis();

System.out.println(searcher.sequentialSearch(index));

long endTimeSequential;
endTimeSequential = System.currentTimeMillis();

long totalTimeSequential;
totalTimeSequential = endTimeSequential-startTimeSequential;
System.out.println("sequential search time: " + totalTimeSequential + " milliseconds");

/* call the method that searches array items
* for each of the values in array targets
* using the binary search algorithm
* print the approximate elapsed time in milliseconds
* For the FIRST FIVE searches print out the index
* where target value was found or print -1 if it was not found
*/
long startTimeBinary;
startTimeBinary = System.currentTimeMillis();

System.out.println(searcher.binarySearch(index));

long endTimeBinary;
endTimeBinary = System.currentTimeMillis();

long totalTimeBinary;
totalTimeBinary = endTimeBinary - startTimeBinary;
System.out.println("binary search time: " + totalTimeBinary + " milliseconds");
}
}

编辑:输出应该是这样的>

395

986

-1

14

-1

顺序搜索时间:40毫秒

395

986

-1

14

-1

二分查找时间:0毫秒

最佳答案

您的sequentialSearch完全错误,您甚至没有访问其中的数组。

您的搜索方法都调用loadItemsAndTargets。它应该只被调用一次

binarySearch 仅适用于排序数组。您的数组未排序。

即使您纠正了所有这些错误。请注意,您的数组将包含重复项。因此,如果尝试比较 sequentialSearchbinarySearch 之间的索引,它们可能不匹配,除非您的 binarySearch 返回下限

关于java - 二分/顺序搜索,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8060224/

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