java - 创建一个 int 类型的随机数组。 java

Question

我需要创建一个随机的 int 数组并按我自己的类对其进行排序。这是我制作数组的地方:

public class MyProgram9{
 public static void main(String[] args){

    int[] list = new int[10];
    for (int i=0; i<10; i++){
        int n = (int)(Math.random()*9 + 1);
        list[i] = n;

        System.out.println(list[i] + " ");
    }
    list.QuickSort();
 }
}

然后我尝试使用另一个类对其进行排序(QuickSort 类)。我的问题是如何从同一文件夹实现此类，以便我可以使用它。这是快速排序类:

public class QuickSort{
public static void quickSort(int[] list){
quickSort(list, 0, list.length - 1);
  }

private static void quickSort(int[] list, int first, int last) {
if (last > first) {
  int pivotIndex = partition(list, first, last);
  quickSort(list, first, pivotIndex - 1);
  quickSort(list, pivotIndex + 1, last);
}
 }

 /** Partition the array list[first..last] */
 private static int partition(int[] list, int first, int last) {
int pivot = list[first]; // Choose the first element as the pivot
int low = first + 1; // Index for forward search
int high = last; // Index for backward search

while (high > low) {
  // Search forward from left
  while (low <= high && list[low] <= pivot)
    low++;

  // Search backward from right
  while (low <= high && list[high] > pivot)
    high--;

  // Swap two elements in the list
  if (high > low) {
    int temp = list[high];
    list[high] = list[low];
    list[low] = temp;
  }
}

while (high > first && list[high] >= pivot)
  high--;

// Swap pivot with list[high]
if (pivot > list[high]) {
  list[first] = list[high];
  list[high] = pivot;
  return high;
}
else {
  return first;
   }
  }
}

对所有信息感到抱歉。

Answer 1

如果您的意思是如何连接这两个类，您的代码是错误的。您必须对数组调用静态快速排序方法。喜欢:

public class MyProgram9{
 public static void main(String[] args){

    int[] list = new int[10];
    for (int i=0; i<10; i++){
        int n = (int)(Math.random()*9 + 1);
        list[i] = n;

        System.out.println(list[i] + " ");
    }
    QuickSort.quicksort(list);
 }
}