gpt4 book ai didi

java - 未正确加密和解​​密

转载 作者:行者123 更新时间:2023-12-02 00:32:07 24 4
gpt4 key购买 nike

我编写的用于加密和解密的以下 AES 类有些奇怪。当我复制 AES 对象并选择加密纯文本,然后我立即尝试解密刚刚加密的文本时,它不会完全解密(并且每次的解密方式都不同)。

例如我用一个简单的 JSP 来初始化它,如下所示:

<%@page import="com.myclass.util.AES"%>
<%
String hexMessage = "0xe800a86d90d2074fbf339aa70b6d0f62f047db15ef04c86b488a1dda3c6c4f2f2bbb444a8c709bbb4c29c7ff1f1e";
String keyText = "12345678abcdefgh";//*/

AES e = new AES();
//e.setKey(keyText);
String plaintext = "This should decode & encode!";
String ciphertext = e.encrypt(plaintext);
out.println(ciphertext);
out.println("<BR>");
out.println(e.decrypt(ciphertext));
%>

输出因每个页面加载而异:一次:

0x663D64E6A0AE455AB3D25D5AF2F77C72202627EBA068E6DEBE5F22C31
This should decoÁdìmèåV4ÉkÓ

另一个:

0x5F5CF31961505F01EA9D5B7D7BFC656BD3117725D2EA041183F48
This s2??XêêÈ&ÀܧF?ÒDÒ­?

等等:

0xC7178A34C59F74E5D68F7CE5ED655B670A0B4E715101B4DDC2122460E8
Tà@¼R×ËÖ?_U?xÎÚ?Ba?b4r!©F

我创建的类如下:

package com.myclass.util;

import java.io.UnsupportedEncodingException;
import java.security.InvalidAlgorithmParameterException;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import java.security.NoSuchProviderException;
import java.security.Security;
import java.util.regex.Pattern;
import javax.crypto.*;
import javax.crypto.spec.*;

public class AES {
private static String provider = "AES/CTR/NoPadding";
private static String providerkey = "AES";
private static int size = 128;
private SecretKeySpec key;
private Cipher cipher;
private byte[] ivBytes = new byte[size/8];
private IvParameterSpec ivSpec = new IvParameterSpec(ivBytes);


public AES() throws NoSuchAlgorithmException, NoSuchPaddingException, NoSuchProviderException{
Security.addProvider(new org.bouncycastle.jce.provider.BouncyCastleProvider());
KeyGenerator kgen = KeyGenerator.getInstance(providerkey);
kgen.init(size); // 192 and 256 bits may not be available
SecretKey skey = kgen.generateKey();
byte[] raw = skey.getEncoded();
key = new SecretKeySpec(raw, providerkey);
cipher = Cipher.getInstance(provider);
for(int x = 0; x < (size/8); x++)
ivBytes[x] = 00;
ivSpec = new IvParameterSpec(ivBytes);
}

public void setKey(String keyText){
byte[] bText = new byte[size/8];
bText = keyText.getBytes();
key = new SecretKeySpec(bText, providerkey);
}

public void setIV(String ivText){
setIV(ivText.getBytes());
}

public void setIV(byte[] ivByte){
byte[] bText = new byte[size/8];
bText = ivByte;
ivBytes = bText;
ivSpec = new IvParameterSpec(ivBytes);
}

public String encrypt(String message) throws InvalidKeyException, IllegalBlockSizeException, BadPaddingException, InvalidAlgorithmParameterException{
cipher.init(Cipher.ENCRYPT_MODE, key, ivSpec);
byte[] encrypted = cipher.doFinal(message.getBytes());
return byteArrayToHexString(encrypted);
}
public String decrypt(String hexCiphertext) throws IllegalBlockSizeException, BadPaddingException, InvalidKeyException, InvalidAlgorithmParameterException, UnsupportedEncodingException{
cipher.init(Cipher.DECRYPT_MODE, key, ivSpec);
byte[] dec = hexStringToByteArray(hexCiphertext);
byte[] decrypted = cipher.doFinal(dec);
return new String(decrypted);
}

private static String byteArrayToHexString( byte [] raw ) {
String hex = "0x";
String s = new String(raw);
for(int x = 0; x < s.length(); x++){
char[] t = s.substring(x, x + 1).toCharArray();
hex += Integer.toHexString((int) t[0]).toUpperCase();
}
return hex;
}

private static byte[] hexStringToByteArray(String hex) {
Pattern replace = Pattern.compile("^0x");
String s = replace.matcher(hex).replaceAll("");

byte[] b = new byte[s.length() / 2];
for (int i = 0; i < b.length; i++){
int index = i * 2;
int v = Integer.parseInt(s.substring(index, index + 2), 16);
b[i] = (byte)v;
}
return b;
}


}

根据不同的结果,我想知道 IV 是否出了什么问题,但我不太明白为什么......

[编辑]如果我硬编码解密仍然不同,看起来它不是IV。如果我对 key 进行硬编码,它会停止变化,但仍然无法正确解密文本:-(。

--------------------- ===================== ----- ----------------

根据 owlstead 的代码和建议添加我在下面创建的最终解决方案。它执行以下操作:
1) 初始化时有随 secret 钥和 iv。
2) 允许您将 key 或 iv 指定为常规字符串或十六进制编码字符串。
3) 自动截断或空填充任何给定的 key 或 iv 以使其达到适当的长度。

注意:第 3 项可能被视为极其不安全,因为它允许您做一些愚蠢的事情。出于我的目的,我需要它,但请谨慎使用。如果您对 key 使用短字符串进行空填充,您的内容将不会非常安全。

--------------------- ===================== ----- ----------------

package com.myclass.util;

import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
import java.security.InvalidAlgorithmParameterException;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import java.security.NoSuchProviderException;
import java.security.spec.InvalidParameterSpecException;
import java.util.regex.Pattern;
import javax.crypto.BadPaddingException;
import javax.crypto.Cipher;
import javax.crypto.IllegalBlockSizeException;
import javax.crypto.KeyGenerator;
import javax.crypto.NoSuchPaddingException;
import javax.crypto.SecretKey;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;

public class AES {
private static Charset PLAIN_TEXT_ENCODING = Charset.forName("UTF-8");
private static String CIPHER_TRANSFORMATION = "AES/CTR/NoPadding";
private static String KEY_TYPE = "AES";
private static int KEY_SIZE_BITS = 128;

private SecretKey key;
private Cipher cipher = Cipher.getInstance(CIPHER_TRANSFORMATION);
private byte[] ivBytes = new byte[KEY_SIZE_BITS/8];

public AES() throws NoSuchAlgorithmException, NoSuchPaddingException, NoSuchProviderException, InvalidParameterSpecException, InvalidKeyException, InvalidAlgorithmParameterException{
KeyGenerator kgen = KeyGenerator.getInstance(KEY_TYPE);
kgen.init(KEY_SIZE_BITS);
key = kgen.generateKey();
cipher.init(Cipher.ENCRYPT_MODE, key);
ivBytes = cipher.getParameters().getParameterSpec(IvParameterSpec.class).getIV();
}

public String getIVAsHex(){
return byteArrayToHexString(ivBytes);
}

public String getKeyAsHex(){
return byteArrayToHexString(key.getEncoded());
}

public void setStringToKey(String keyText){
setKey(keyText.getBytes());
}

public void setHexToKey(String hexKey){
setKey(hexStringToByteArray(hexKey));
}

private void setKey(byte[] bArray){
byte[] bText = new byte[KEY_SIZE_BITS/8];
int end = Math.min(KEY_SIZE_BITS/8, bArray.length);
System.arraycopy(bArray, 0, bText, 0, end);
key = new SecretKeySpec(bText, KEY_TYPE);
}

public void setStringToIV(String ivText){
setIV(ivText.getBytes());
}

public void setHexToIV(String hexIV){
setIV(hexStringToByteArray(hexIV));
}

private void setIV(byte[] bArray){
byte[] bText = new byte[KEY_SIZE_BITS/8];
int end = Math.min(KEY_SIZE_BITS/8, bArray.length);
System.arraycopy(bArray, 0, bText, 0, end);
ivBytes = bText;
}

public String encrypt(String message) throws InvalidKeyException,
IllegalBlockSizeException, BadPaddingException,
InvalidAlgorithmParameterException {
cipher.init(Cipher.ENCRYPT_MODE, key, new IvParameterSpec(ivBytes));
byte[] encrypted = cipher.doFinal(message.getBytes(PLAIN_TEXT_ENCODING));
return byteArrayToHexString(encrypted);
}

public String decrypt(String hexCiphertext)
throws IllegalBlockSizeException, BadPaddingException,
InvalidKeyException, InvalidAlgorithmParameterException,
UnsupportedEncodingException {
cipher.init(Cipher.DECRYPT_MODE, key, new IvParameterSpec(ivBytes));
byte[] dec = hexStringToByteArray(hexCiphertext);
byte[] decrypted = cipher.doFinal(dec);
return new String(decrypted, PLAIN_TEXT_ENCODING);
}

private static String byteArrayToHexString(byte[] raw) {
StringBuilder sb = new StringBuilder(2 + raw.length * 2);
sb.append("0x");
for (int i = 0; i < raw.length; i++) {
sb.append(String.format("%02X", Integer.valueOf(raw[i] & 0xFF)));
}
return sb.toString();
}

private static byte[] hexStringToByteArray(String hex) {
Pattern replace = Pattern.compile("^0x");
String s = replace.matcher(hex).replaceAll("");

byte[] b = new byte[s.length() / 2];
for (int i = 0; i < b.length; i++){
int index = i * 2;
int v = Integer.parseInt(s.substring(index, index + 2), 16);
b[i] = (byte)v;
}
return b;
}

}

最佳答案

重写,内嵌注释。有趣的是,最大的错误是生成十六进制,所以我重写了该方法。它并不完美,但我尽可能保留了您的原始来源。

import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
import java.security.GeneralSecurityException;
import java.security.InvalidAlgorithmParameterException;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import java.security.NoSuchProviderException;
import java.security.Security;
import java.util.regex.Pattern;

import javax.crypto.BadPaddingException;
import javax.crypto.Cipher;
import javax.crypto.IllegalBlockSizeException;
import javax.crypto.NoSuchPaddingException;
import javax.crypto.SecretKey;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;

import org.bouncycastle.jce.provider.BouncyCastleProvider;

/*
* Add state handling! Don't allow same key/iv for encrypting different cipher text!
*/
public class AES {

private static Charset PLAIN_TEXT_ENCODING = Charset.forName("UTF-8");
private static String CIPHER_TRANSFORMATION = "AES/CTR/NoPadding";
private static String KEY_TYPE = "AES";
// 192 and 256 bits may not be available
private static int KEY_SIZE_BITS = 128;

private Cipher cipher;
private SecretKey key;
private IvParameterSpec iv;

static {
// only needed if the platform does not contain CTR encryption by default
if (Security.getProvider(BouncyCastleProvider.PROVIDER_NAME) == null) {
// only needed for some platforms I presume
Security.addProvider(new org.bouncycastle.jce.provider.BouncyCastleProvider());
}
}

public AES() throws NoSuchAlgorithmException, NoSuchPaddingException,
NoSuchProviderException {
// not much use without a getter
// final KeyGenerator kgen = KeyGenerator.getInstance(KEY_TYPE);
// kgen.init(KEY_SIZE_BITS);
// key = kgen.generateKey();
cipher = Cipher.getInstance(CIPHER_TRANSFORMATION);
}

public void setKeyHex(String keyText) {

byte[] bText = hexStringToByteArray(keyText);
if (bText.length * Byte.SIZE != KEY_SIZE_BITS) {
throw new IllegalArgumentException(
"Wrong key size, expecting " + KEY_SIZE_BITS / Byte.SIZE + " bytes in hex");
}
key = new SecretKeySpec(bText, KEY_TYPE);
}

public void setIVHex(String ivText) {
byte[] bText = hexStringToByteArray(ivText);
if (bText.length != cipher.getBlockSize()) {
throw new IllegalArgumentException(
"Wrong IV size, expecting " + cipher.getBlockSize() + " bytes in hex");
}
iv = new IvParameterSpec(bText);
}

public String encrypt(String message) throws InvalidKeyException,
IllegalBlockSizeException, BadPaddingException,
InvalidAlgorithmParameterException {
cipher.init(Cipher.ENCRYPT_MODE, key, iv);
byte[] encrypted = cipher.doFinal(message.getBytes(PLAIN_TEXT_ENCODING));
return byteArrayToHexString(encrypted);
}

public String decrypt(String hexCiphertext)
throws IllegalBlockSizeException, BadPaddingException,
InvalidKeyException, InvalidAlgorithmParameterException,
UnsupportedEncodingException {
cipher.init(Cipher.DECRYPT_MODE, key, iv);
byte[] dec = hexStringToByteArray(hexCiphertext);
byte[] decrypted = cipher.doFinal(dec);
return new String(decrypted, PLAIN_TEXT_ENCODING);
}

private static String byteArrayToHexString(byte[] raw) {
StringBuilder sb = new StringBuilder(2 + raw.length * 2);
sb.append("0x");
for (int i = 0; i < raw.length; i++) {
sb.append(String.format("%02X", Integer.valueOf(raw[i] & 0xFF)));
}
return sb.toString();
}

// better add some input validation
private static byte[] hexStringToByteArray(String hex) {
Pattern replace = Pattern.compile("^0x");
String s = replace.matcher(hex).replaceAll("");

byte[] b = new byte[s.length() / 2];
for (int i = 0; i < b.length; i++) {
int index = i * 2;
int v = Integer.parseInt(s.substring(index, index + 2), 16);
b[i] = (byte) v;
}
return b;
}

public static void main(String[] args) {
try {
String key = "0x000102030405060708090A0B0C0D0E0F";
String iv = "0x000102030405060708090A0B0C0D0E0F";

String text = "Owlsteads answer";
AES aes = new AES();
aes.setKeyHex(key);
aes.setIVHex(iv);
String cipherHex = aes.encrypt(text);
System.out.println(cipherHex);
String deciphered = aes.decrypt(cipherHex);
System.out.println(deciphered);
} catch (GeneralSecurityException e) {
throw new IllegalStateException("Something is rotten in the state of Denmark", e);
} catch (UnsupportedEncodingException e) {
// not always thrown even if decryption fails, add integrity check such as MAC
throw new IllegalStateException("Decryption and/or decoding plain text message failed", e);
}
}
}

关于java - 未正确加密和解​​密,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8771246/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com