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java - TCP 聊天服务器

转载 作者:行者123 更新时间:2023-12-02 00:31:10 26 4
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我正在修改我发现的关于如何创建接受多个客户端的 TCP 聊天服务器的教程。我最终也会创建一个客户端类,但到目前为止我正在使用 TELNET 测试它。

我希望服务器不断检查输入,以便我可以使用关键字来执行服务器功能。因此,字符串单词“EXIT”用于断开客户端连接,字符串单词“Name:”用于打印“OK”。

这就是我的想法,但它不起作用:

 public void run()  
{
String line;
try
{
while(true)
{
if (input.readline("EXIT"))//Should close and remove client
{
clients.remove(this);
users.remove(name);
break;
}
if(input.readline("Name:"))//Should print OK with username
{
System.out.println("OK");
}
boradcast(name,line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
}

}

这是整个服务器类

// Chat Server runs at port no. 9020
import java.io.*;
import java.util.*;
import java.net.*;
import static java.lang.System.out;

public class TCPServer
{
Vector<String> users = new Vector<String>();
Vector<HandleClient> clients = new Vector<HandleClient>();

int PORT = 9020;
int NumClients = 10;

public void process() throws Exception
{
ServerSocket server = new ServerSocket(PORT,NumClients);
out.println("Server Connected...");
while( true)
{
Socket client = server.accept();
HandleClient c = new HandleClient(client);
clients.add(c);
} // end of while
}

public static void main(String ... args) throws Exception
{
new TCPServer().process();
} // end of main

public void boradcast(String user, String message)
{
// send message to all connected users
for (HandleClient c : clients)
if (!c.getUserName().equals(user))
{
c.sendMessage(user,message);
}
}

class HandleClient extends Thread
{
String name = "";
BufferedReader input;
PrintWriter output;

public HandleClient(Socket client) throws Exception
{
// get input and output streams
input = new BufferedReader(new InputStreamReader(client.getInputStream())) ;
output = new PrintWriter (client.getOutputStream(),true);
output.println("Welcome to Bob's Chat Server!\n");
// read name
output.println("Please Enter a User Name: ");
name = input.readLine();
users.add(name); // add to vector
output.println("Welcome "+name+" we hope you enjoy your chat today");
start();
}

public void sendMessage(String uname,String msg)
{
output.println( uname + ":" + msg);
}

public String getUserName()
{
return name;
}

public void run()
{
String line;
try
{
while(true)
{
if (input.readline("EXIT"))
{
clients.remove(this);
users.remove(name);
break;
}
if(input.readline(name))
{
System.out.println("OK");
}
boradcast(name,line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e)
{
System.out.println(e.getMessage());
}
} // end of run()
} // end of inner class
} // end of Server

最佳答案

如果不知道当输入行等于当前用户名时您想要做什么,我认为这更适合您:

    public void run(){
try{
while(true){
String line = input.readLine();

if("EXIT".equals(line)){
clients.remove(this);
users.remove(name);
break;
}else if(name.equals(line)){
System.out.println("OK");
}
boradcast(name, line); // method of outer class - send messages to all
}// end of while
} // try
catch(Exception e){
System.out.println(e.getMessage());
}
} // end of run()

这解决了一些问题:

  • input.readline 不是方法,而是 input.readLine是 - 并且它不接受任何参数。 (这应该显示为编译错误。)
  • 您从未向 line 字符串分配任何内容。
  • 您已多次阅读该行内容。如果它与“EXIT”不匹配,您将读取一个新行来与 name 进行比较 - 丢失用户在上一行中输入的任何内容。

关于java - TCP 聊天服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9047982/

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