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r - 更改 wordcloud 中特定单词的颜色

转载 作者:行者123 更新时间:2023-12-02 00:30:47 25 4
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我想用 R 构建一个词云(我已经使用 wordcloud 包做到了这一点),然后将特定单词涂上某种颜色。目前该函数的行为是根据频率给单词着色(这可能很有用),但单词大小已经做到了这一点,所以我想使用颜色来表达额外的含义。

关于如何为 wordcloud 中的特定单词着色有什么想法吗? (如果 R 中还有另一个词云函数,我不知道我非常愿意走这条路。)

一个模拟示例和我的尝试(我尝试以与绘图函数中的常规绘图相同的方式处理颜色参数):

library(wordcloud)

x <- paste(rep("how do keep the two words as one chunk in the word cloud", 3),
collapse = " ")
X <- data.frame(table(strsplit(x, " ")))
COL <- ifelse(X$Var1 %in% c("word", "cloud", "words"), "red", "black")
wordcloud(X$Var1, X$Freq, color=COL)

编辑:我想补充一点,新版本的 wordcloud(2010 年 1 月 10 日;版本 2.0)[谢谢 Ian Fellows 和 David Robinson] 现在就是这个功能以及其他一些很棒的补充。以下是在 wordcloud 中实现最初目标的代码:

wordcloud(X$Var1, X$Freq, color=COL, ordered.colors=TRUE, random.color=FALSE)

最佳答案

编辑:如评论中所述,下面描述的功能现已添加到 wordcloud 中图书馆。

<小时/>

我的方法是采用 R 函数的代码并对其进行自定义。它只需要更改几行,现在可以采用单一颜色或与单词长度相同的颜色向量。

library(wordcloud)

colored.wordcloud <- function(words,freq,scale=c(4,.5),min.freq=3,max.words=Inf,random.order=TRUE,random.color=FALSE,
rot.per=.1,colors="black",ordered.colors=FALSE,use.r.layout=FALSE,...) {
tails <- "g|j|p|q|y"
last <- 1
nc<- length(colors)

if (ordered.colors) {
if (length(colors) != 1 && length(colors) != length(words)) {
stop(paste("Length of colors does not match length of words",
"vector"))
}
}

overlap <- function(x1, y1, sw1, sh1) {
if(!use.r.layout)
return(.overlap(x1,y1,sw1,sh1,boxes))
s <- 0
if (length(boxes) == 0)
return(FALSE)
for (i in c(last,1:length(boxes))) {
bnds <- boxes[[i]]
x2 <- bnds[1]
y2 <- bnds[2]
sw2 <- bnds[3]
sh2 <- bnds[4]
if (x1 < x2)
overlap <- x1 + sw1 > x2-s
else
overlap <- x2 + sw2 > x1-s

if (y1 < y2)
overlap <- overlap && (y1 + sh1 > y2-s)
else
overlap <- overlap && (y2 + sh2 > y1-s)
if(overlap){
last <<- i
return(TRUE)
}
}
FALSE
}

ord <- rank(-freq, ties.method = "random")
words <- words[ord<=max.words]
freq <- freq[ord<=max.words]
if (ordered.colors) {
colors <- colors[ord<=max.words]
}

if(random.order)
ord <- sample.int(length(words))
else
ord <- order(freq,decreasing=TRUE)
words <- words[ord]
freq <- freq[ord]
words <- words[freq>=min.freq]
freq <- freq[freq>=min.freq]
if (ordered.colors) {
colors <- colors[ord][freq>=min.freq]
}

thetaStep <- .1
rStep <- .05
plot.new()
op <- par("mar")
par(mar=c(0,0,0,0))
plot.window(c(0,1),c(0,1),asp=1)
normedFreq <- freq/max(freq)
size <- (scale[1]-scale[2])*normedFreq + scale[2]
boxes <- list()



for(i in 1:length(words)){
rotWord <- runif(1)<rot.per
r <-0
theta <- runif(1,0,2*pi)
x1<-.5
y1<-.5
wid <- strwidth(words[i],cex=size[i],...)
ht <- strheight(words[i],cex=size[i],...)
#mind your ps and qs
if(grepl(tails,words[i]))
ht <- ht + ht*.2
if(rotWord){
tmp <- ht
ht <- wid
wid <- tmp
}
isOverlaped <- TRUE
while(isOverlaped){
if(!overlap(x1-.5*wid,y1-.5*ht,wid,ht) &&
x1-.5*wid>0 && y1-.5*ht>0 &&
x1+.5*wid<1 && y1+.5*ht<1){
if (!random.color) {
if (ordered.colors) {
cc <- colors[i]
}
else {
cc <- ceiling(nc*normedFreq[i])
cc <- colors[cc]
}
} else {
cc <- colors[sample(1:nc,1)]
}
text(x1,y1,words[i],cex=size[i],offset=0,srt=rotWord*90,
col=cc,...)
#rect(x1-.5*wid,y1-.5*ht,x1+.5*wid,y1+.5*ht)
boxes[[length(boxes)+1]] <- c(x1-.5*wid,y1-.5*ht,wid,ht)
isOverlaped <- FALSE
}else{
if(r>sqrt(.5)){
warning(paste(words[i],
"could not be fit on page. It will not be plotted."))
isOverlaped <- FALSE
}
theta <- theta+thetaStep
r <- r + rStep*thetaStep/(2*pi)
x1 <- .5+r*cos(theta)
y1 <- .5+r*sin(theta)
}
}
}
par(mar=op)
invisible()
}

一些尝试的代码:

colors = c("blue", "red", "orange", "green")
colored.wordcloud(colors, c(10, 5, 3, 9), colors=colors)

关于r - 更改 wordcloud 中特定单词的颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8781700/

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