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java - 为什么这个 if 语句不起作用?

转载 作者:行者123 更新时间:2023-12-02 00:29:06 24 4
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我正在尝试创建一个 if 语句,例如,如果用户没有在两个编辑文本中键入任何内容,那么它会显示一个 toast 并重置所有内容。但由于某种原因,我的代码完全忽略了这一点,而只是转到 else 语句。

有人可以帮忙吗?

我的代码:包 com.gta5news.bananaphone;

import java.io.File;

import android.R.string;
import android.app.Activity;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.Bundle;
import android.os.Environment;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;

public class LogIn extends Activity implements OnClickListener {
Button send;
EditText user;
EditText pass;
CheckBox staySignedIn;
SharedPreferences shareduser;
SharedPreferences sharedpass;
public static String settings = "MySharerdUser";

@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
send = (Button) findViewById(R.id.bLogIn);
user = (EditText) findViewById(R.id.eTuser);
pass = (EditText) findViewById(R.id.eTpassword);
staySignedIn = (CheckBox) findViewById(R.id.Cbstay);
send.setOnClickListener(this);
SharedPreferences settings = getPreferences(MODE_PRIVATE);
String name = settings.getString("name", "");
String password = settings.getString("pwd", "");
user.setText(name);
pass.setText(password);

if (staySignedIn.isChecked()) {
SharedPreferences MySharedUser = getPreferences(MODE_PRIVATE);
settings.edit().putString("name", user.getText().toString())
.putString("pwd", pass.getText().toString()).commit();
}

if (user.length() > 0)
;

}

public void onClick(View v) {
// TODO Auto-generated method stub
switch (v.getId()) {
case R.id.bLogIn:
if (user.length() < 0)
Toast.makeText(this,
"Try to type in your username and password again!",
Toast.LENGTH_LONG).show();
else {
String u = user.getText().toString();
String p = pass.getText().toString();
Bundle send = new Bundle();
send.putString("key", u);
send.putString("key", p);
Intent a = new Intent(LogIn.this, FTPClient.class);
startActivity(a);
Toast.makeText(this, "Yay, you signed in!", Toast.LENGTH_LONG)
.show();
break;
}
}

}

}

最佳答案

 if (user.length() == 0)  

尝试一下,因为 user.length() 永远不会小于

关于java - 为什么这个 if 语句不起作用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9486229/

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