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camera - 无法获取相机拍摄的图像的文件名

转载 作者:行者123 更新时间:2023-12-02 00:27:44 25 4
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我正在尝试构建一个应用程序,在其中我可以使用相机捕获图像并将其保存到图库。但我无法获取图像的文件名。如果我从相机胶卷中选择图像,那么我可以获取所选图像的文件名。但是当我在应用程序中使用相机捕获图像时,它返回文件名“null”。这是我使用 UIImagePickerController

保存并从图库中选择图像的代码
- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{

UIImage *chosenImage = [self scaleAndRotateImage:[info valueForKey:UIImagePickerControllerOriginalImage]];
NSString *mediaType = info[UIImagePickerControllerMediaType];
self.userProfileImage.image = chosenImage;

if ([mediaType isEqualToString:(NSString *)kUTTypeImage]) {
UIImage *image = info[UIImagePickerControllerOriginalImage];

if (newMedia)
UIImageWriteToSavedPhotosAlbum(image,
self,
@selector(image:finishedSavingWithError:contextInfo:),
nil);
}

imageRotation=[NSString stringWithFormat:@"%f %f %f",acos (self.userProfileImage.transform.a), asin (self.userProfileImage.transform.b), atan2(self.userProfileImage.transform.b, self.userProfileImage.transform.a)];
CGFloat angle = [(NSNumber *)[self.userProfileImage valueForKeyPath:@"layer.transform.rotation.z"] floatValue];
NSLog(@"%f", angle);

NSURL *referenceURL = [info objectForKey:UIImagePickerControllerReferenceURL];
ALAssetsLibrary *assetLibrary = [ALAssetsLibrary new];

[assetLibrary assetForURL:referenceURL
resultBlock:^(ALAsset *asset) {
ALAssetRepresentation *assetRep = [asset defaultRepresentation];
fileName = [assetRep filename];
NSLog(@"File name = %@", fileName);
}

failureBlock:^(NSError *error) {
NSLog(@"%@", error);
}];

[[UIApplication sharedApplication] setStatusBarStyle:UIStatusBarStyleLightContent];
[[UIApplication sharedApplication] setStatusBarHidden:YES];
[picker dismissViewControllerAnimated:YES completion:nil];
imageChanged=TRUE;
}

此代码用于保存捕获的图像

- (void)image:(UIImage *)image didFinishSavingWithError:(NSError *)error contextInfo:(void *)contextInfo {
UIAlertView *alert;
//NSLog(@"Image:%@", image);
if (error) {
alert = [[UIAlertView alloc] initWithTitle:@"Error!"
message:[error localizedDescription]
delegate:nil
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];

}
}

我陷入了如何获取捕获图像的文件名的困境。我的代码做错了什么?请建议我任何更正或解决方案。任何帮助,将不胜感激 。提前致谢

最佳答案

以下是我如何获取使用 UIImagePickerController 选择的文件、视频或照片的文件名:

- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
@try {
self.myinfo = info;
DDLogDebug(@"MediaListView - Dismissing camera ui...");
[self.cameraUI dismissViewControllerAnimated:YES completion:nil];

mediaURL = [info objectForKey:UIImagePickerControllerMediaURL];
DDLogDebug(@"MediaListView - Media url = %@", mediaURL);

NSString *mediaType = [info objectForKey:UIImagePickerControllerMediaType];
DDLogDebug(@"MediaListView - Selected mediaType: %@", mediaType);

// This is a video
if(mediaURL) {
DDLogDebug(@"MediaListView - This is a video");

// Just recorded video
if (self.source == UIImagePickerControllerSourceTypeCamera) {
DDLogDebug(@"MediaListView - This is a new video, saving to photos album...");

// Save video before getting its name
ALAssetsLibrary *library = [ALAssetsLibrary new];

[library writeVideoAtPathToSavedPhotosAlbum:mediaURL completionBlock:^(NSURL *assetURL, NSError *error){
if (error) {
DDLogDebug(@"MediaListView - Failed to save the photo to photos album...");
} else {
DDLogDebug(@"MediaListView - Video saved to photos album...");

// Video saved, we can get its name
[self getNameFromUrl:assetURL];
}
}];
}
else {
DDLogDebug(@"MediaListView - This is an existing video, getting name...");
// Get video name
[self getNameFromUrl:[info objectForKey:UIImagePickerControllerReferenceURL]];
}
}
// This is a photo
else {
DDLogDebug(@"MediaListView - This is a photo...");
self.originalImage = (UIImage*)[info objectForKey:UIImagePickerControllerOriginalImage];

// Just taken photo
if (self.source == UIImagePickerControllerSourceTypeCamera) {
DDLogDebug(@"MediaListView - This is a new photo, saving to photos album...");

// Save photo to album
ALAssetsLibrary *library = [ALAssetsLibrary new];

[library writeImageToSavedPhotosAlbum:[self.originalImage CGImage]
orientation:(ALAssetOrientation)[self.originalImage imageOrientation]
completionBlock:^(NSURL *assetURL, NSError *error){
if (error) {
DDLogDebug(@"MediaListView - Failed to save the vide to photos album...");
} else {
DDLogDebug(@"MediaListView - Photo saved to photos album...");

// Get photo name
[self getNameFromUrl:assetURL];
}
}];
}
else {
DDLogDebug(@"MediaListView - This is an existing image, getting name...");
// Get photo name
[self getNameFromUrl:[info objectForKey:@"UIImagePickerControllerReferenceURL"]];
}
}
}
@catch (NSException *exception) {
DDLogError(@"MediaListView - Exception in picker didFinishPickingMediaWithInfo");
DDLogError(@"MediaListView - %@", [exception description]);
}
}

- (void)getNameFromUrl(NSURL*)url {
@try {
DDLogDebug(@"MediaListView - GetNameFromUrl");

ALAssetsLibraryAssetForURLResultBlock resultblock = ^(ALAsset *asset) {

if (asset == nil) {
DDLogError(@"MediaListView - SaveAssetData - asset is nil!");
return;
}

DDLogDebug(@"MediaListView - SaveAssetData - Got asset data: %@", asset.description);
ALAssetRepresentation *assetRep = [asset defaultRepresentation];

NSString *fileName = [assetRep filename];
DDLogDebug(@"MediaListView - SaveAssetData - File name = %@", fileName);
};

ALAssetsLibraryAccessFailureBlock failureblock = ^(NSError *error) {
DDLogError(@"MediaListView - SaveAssetData - Failed to get name%@", error);
};

ALAssetsLibrary *library = [ALAssetsLibrary new];
[library assetForURL:url resultBlock:resultblock failureBlock:failureblock];
}
@catch (NSException *exception) {
DDLogError(@"MediaListView - Exception in saveAssetData");
DDLogError(@"MediaListView - %@", [exception description]);
}
}

关于camera - 无法获取相机拍摄的图像的文件名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28272382/

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