java - 使用正则表达式提取网址的特定部分

Question

我想通过在java中使用正则表达式来提取位于中间的url的一部分这就是我尝试过的，检测 java+regex 的主要问题是它位于网址最后一部分的中间，我不知道如何忽略它后面的字符，我的正则表达式只是忽略之前它:

   String regex = "https://www\\.google\\.com/(search)?q=([^/]+)/";
String   url = "https://www.google.com/search?q=regex+java&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a";
Pattern pattern = Pattern.compile (regex);
Matcher matcher = pattern.matcher (url);

if (matcher.matches ())
{
    int n = matcher.groupCount ();
    for (int i = 0; i <= n; ++i)
        System.out.println (matcher.group (i));
}
    }

结果应该是 regex+java 甚至是 regex java 。但我的代码没有成功...

Answer 1

尝试:

    String regex = "https://www\\.google\\.com/search\\?q=([^&]+).*";
    String   url = "https://www.google.com/search?q=regex+java&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a";
    Pattern pattern = Pattern.compile (regex);
    Matcher matcher = pattern.matcher (url);

    if (matcher.matches ())
    {
        int n = matcher.groupCount ();
        for (int i = 0; i <= n; ++i)
            System.out.println (matcher.group (i));
    }

结果是:

https://www.google.com/search?q=regex+java&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a
regex+java

编辑

打印前替换所有加号:

for (int i = 0; i <= n; ++i) {
   String str = matcher.group (i).replaceAll("\\+", " ");
   System.out.println (str);
}