java - 用于匹配 mp3 URL 的正则表达式

Question

如何使用 REGEX 获取 mp3 url？

这个 mp3 url，例如:

https://www.soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3

This is a what I've tried so far but I want it to only accept a url with '.mp3' on the end.

(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]

Answer 1

这个表达式可能会传递您想要的输入:

^(https?|ftp|file):\/\/(www.)?(.*?)\.(mp3)$

如果你想给它添加更多的边界，你可以这样做。例如，您可以添加一个字符列表而不是 .*.

我添加了几个捕获组，以便在必要时调用。

正则表达式

如果这不是您想要的表达式，您可以在 regex101.com 中修改/更改您的表达式.

正则表达式电路

您还可以在 jex.im 中可视化您的表情:

const regex = /^(https?|ftp|file):\/\/(www.)?(.*?)\.(mp3)$/gm;
const str = `https://www.soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3
http://soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3
http://www.soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3
ftp://soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3
file://localhost/examples/mp3/SoundHelix-Song-1.mp3
file://localhost/examples/mp3/SoundHelix-Song-1.wav
file://localhost/examples/mp3/SoundHelix-Song-1.avi
file://localhost/examples/mp3/SoundHelix-Song-1.m4a`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

Java 测试

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "^(https?|ftp|file):\\/\\/(www.)?(.*?)\\.(mp3)$";
final String string = "https://www.soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3\n"
     + "http://soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3\n"
     + "http://www.soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3\n"
     + "ftp://soundhelix.com/examples/mp3/SoundHelix-Song-1.mp3\n"
     + "file://localhost/examples/mp3/SoundHelix-Song-1.mp3\n"
     + "file://localhost/examples/mp3/SoundHelix-Song-1.wav\n"
     + "file://localhost/examples/mp3/SoundHelix-Song-1.avi\n"
     + "file://localhost/examples/mp3/SoundHelix-Song-1.m4a";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
    System.out.println("Full match: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
        System.out.println("Group " + i + ": " + matcher.group(i));
    }
}