java - 程序需要循环 X 次，无论输入如何，都只会运行一次。没有抛出错误

Question

无论用户输入多少次，程序都需要运行 Dice.java，只会运行一次并且不会抛出任何错误。我也无法证明任何事情，但感觉输出有一个模式。

什么都尝试了一点。

DiceGame1.java - 充当主循环，获取用户想要一次滚动的骰子数量，并处理主循环。

import java.util.Scanner;

public class DiceGame1
{
    public static int mainloop;
    public static void main(String [] args)
    {
        mainloop = 0;
        Scanner OBJ_USERINPUT = new Scanner(System.in);
        System.out.println("How many dice to roll: ");
        int VAR_HOWMANY = OBJ_USERINPUT.nextInt();
        while (mainloop < 1)
        {
            //Create a for loop that will run X amount of times
            for(int i =0; i< VAR_HOWMANY; i++)
            {
                Dice.RollDie();
                RunAgain.RunAgain();
            }
        }
}

}

Dice.java - 旨在完成滚动骰子的实际肮脏工作，然后将其交回给 DiceGame1.java 以让它知道再次运行。

import java.util.Random;
public class Dice 
{
    public static void RollDie()
    {
        Random DIEROLL = new Random();
        //the integer randomInteger equals whatever the DIEROLL object generates.
        int randomInteger = DIEROLL.nextInt(6);
        //Add one to the integer randomInteger so 0 doesn't appear
        randomInteger = randomInteger+1;
        // Prints out the generated number
        switch (randomInteger)
        {
        case 1:
            System.out.println("1");
        case 2:
            System.out.println("2");
        case 3:
            System.out.println("3");
        case 4:
            System.out.println("4");
        case 5:
            System.out.println("5");
        case 6:
            System.out.println("6");
        }
    }
}

RunAgain.java - 目的是让DieGame1.java无限循环运行多长时间。

import java.util.Scanner;
public class RunAgain 
{
    public static void RunAgain()
    {
        String userinput;
        Scanner keyboard = new Scanner(System.in);
        System.out.print("Run again? Y/N: ");
        userinput = keyboard.nextLine();
        if (userinput.equals ("Y"))
        {
        System.out.println("======================================");
        }
        else
        {
            keyboard.close();
            System.exit(0);
        }
    }
}

Answer 1

您在错误的位置调用 RunAgain()，并且在 switch 语句中每次使用 case 后都没有使用 break在这里它正在工作:

import java.util.Random;
import java.util.Scanner;

class DiceGame1
{
    public static int mainloop;
    public static void main(String [] args)
    {
        mainloop = 0;
        Scanner OBJ_USERINPUT = new Scanner(System.in);
        System.out.println("How many dice to roll: ");
        int VAR_HOWMANY = Integer.parseInt(OBJ_USERINPUT.nextLine());
        while (mainloop < 1)
        {
            //Create a for loop that will run X amount of times
            for(int i =0; i < VAR_HOWMANY; i++)
            {
                Dice.RollDie();
            }
            RunAgain.RunAgain();
        }
    }
}
class Dice
{
    public static void RollDie()
    {
        Random DIEROLL = new Random();
        //the integer randomInteger equals whatever the DIEROLL object generates.
        int randomInteger = DIEROLL.nextInt(6);
        //Add one to the integer randomInteger so 0 doesn't appear
        randomInteger = randomInteger+1;
        // Prints out the generated number
        switch (randomInteger)
        {
            case 1:
                System.out.println("1");
                break;
            case 2:
                System.out.println("2");
                break;
            case 3:
                System.out.println("3");
                break;
            case 4:
                System.out.println("4");
                break;
            case 5:
                System.out.println("5");
                break;
            case 6:
                System.out.println("6");
                break;
        }
    }
}
class RunAgain
{
    public static void RunAgain()
    {
        String userinput;
        Scanner keyboard = new Scanner(System.in);
        System.out.print("Run again? Y/N: ");
        userinput = keyboard.nextLine();
        System.out.println(userinput);
        if (userinput.equalsIgnoreCase ("Y"))
        {
            System.out.println("======================================");
        }
        else
        {
            keyboard.close();
            System.exit(0);
        }
    }
}