java - 要求用户在JAVA中递归输入特定范围之间的值？

Question

我正在用Java编写一段代码，系统会要求用户输入1到10之间的整数(包括两者)，如果该值超出范围，它应该递归地要求用户再次输入值。最后我必须打印该范围内的值。下面是我的代码:

`导入java.util.Scanner；公共(public)类输入整数{

public static void main(String[] args) {
    // TODO Auto-generated method stub
    System.out.println("Enter first Integer between 1 and 10 (both inclusive):");
    Scanner sc = new Scanner(System.in);
    int num1 = isInRange(sc, sc.nextInt());

    System.out.println("Enter Second Integer between 1 and 10 (both inclusive):");
    int num2 = isInRange(sc, sc.nextInt());

    System.out.println("Num 1 is "+num1+"\nNum 2 is "+num2);    
    sc.close();
}

public static int isInRange(Scanner scanner, int num) {
    if(num<1 || num>10) {
        System.out.println("WRONG INPUT. PLease enter Integer between 1 and 10 (both inclusive):");
        num =scanner.nextInt();
        isInRange(scanner, num);

    }
    return num;
}

}`

这将是我的输出:

我面临的问题是，当我输入错误的值并且最终当我输入正确的值时，它会打印我第二次输入的值。假设我输入了 8 个超出范围的值，之后我的第 9 个值在范围内，因此它将打印第二次输入的值。

Answer 1

您错过了一些细节:

public static int isInRange(Scanner scanner, int num) {
                if(num<1 || num>10) {
                    System.out.println("WRONG INPUT. PLease enter Integer between 1 and 10 (both inclusive):");
                    num = scanner.nextInt();
                    num = isInRange(scanner, num); // add "num = " at the beginning of the line
                }
                return num;
            }

isInRange() 返回一个您忘记设置为 num 的整数。