java - 创建一个生成新 DatagramSockets 的循环？

Question

嗨，我想循环遍历我拥有的 n 个端口的列表，并为每个端口创建一个 DatagramSocket:

for(int i = 0; i < portList.size(); i++) {
    DatagramSocket socket[i] = new DatagramSocket();
    socket[i].connect(InetAddress.getLocalHost(), portList.get(i));
}

我知道我不应该使用 socket[i] 。只是为了表达我的意思，上面会生成:

DatagramSocket socket1 = new DatagramSocket();
socket1.connect(InetAddress.getLocalHost(), 2000);

DatagramSocket socket2 = new DatagramSocket();
socket2.connect(InetAddress.getLocalHost(), 2001);

DatagramSocket socket3 = new DatagramSocket();
socket3.connect(InetAddress.getLocalHost(), 2002);

DatagramSocket socket4 = new DatagramSocket();
socket4.connect(InetAddress.getLocalHost(), 2003);

我不太擅长 Java，所以这可能是一个愚蠢的问题:P

Answer 1

首先使用ArrayList来存储您的套接字:

ArrayList<DatagramSocket> socketList = new ArrayList<DatagramSocket>();
socketList.add(new DatagramSocket());
socketList.add(new DatagramSocket());
socketList.add(new DatagramSocket());
socketList.add(new DatagramSocket());

然后循环访问socketList:

for(int i = 0; i < portList.size(); i++) {
    socketList.get(i).connect(InetAddress.getLocalHost(), portList.get(i));
}

假设您有相同数量的端口，并在 socketList 中添加了 DatagramSocket。否则，它将在循环中的某个位置抛出一个 NullPointer。

更新

来自user1753100的解决方案:

ArrayList<DatagramSocket> socketList = new ArrayList<DatagramSocket>();
for (int j = 0; j < portList.size(); j++) {
    socketList.add(new DatagramSocket());
}