Java正则表达式替换为捕获长度

Question

String pw="pw:(abc)";//Maybe "pw:(12)","pw:(ab123)"...
pw=pw.replaceFirst("\\(.+\\)", "*");

//pw == result:pw:*

我想要结果:pw:*****。 (abc) 必须是 * x 5

星号的数量等于内容的长度被匹配

我可以仅使用String.replaceFirst或String.replaceAll来实现它吗？

Answer 1

    String var = "lalala(pw:)()pw:(abc12)lalala()(pw:(a12)pw:() lala";

    for(;;){
        String oldVar= var;
        var = var.replaceAll("(pw\\:\\()([*]{0,})([a-zA-Z0-9]{1})(.{1,})", "$1$2*$4");
        if(oldVar.equals(var)){
            break;
        }
    }
    var = var.replaceAll("(pw\\:)\\(([*]{1,})\\)","$1*$2*");
    System.out.println(var);


RESULT: lalala(pw:)()pw:*******lalala()(pw:*****pw:() lala