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java - Kotlin ViewPager2 : Class 'ScreenSlidePagerAdapter' is not abstract and does not implement base class member

转载 作者:行者123 更新时间:2023-12-02 00:06:08 25 4
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嗨,我正在学习如何制作 Android 应用程序,并尝试添加 viewpager...我一直在关注这里的教程:https://developer.android.com/training/animation/screen-slide-2

但是我似乎收到错误:类“ScreenSlidePagerAdapter”不是抽象的,并且没有实现抽象基类成员@NonNull public abstract fun createFragment(p0:Int):在androidx.viewpager2.adapter中定义的 fragment .FragmentStateAdapter

我的代码与教程 ScreenSlidePagerActivity 类几乎相同,所以我不确定问题是什么!

package com.main.treasurex.ui.home


import android.os.Bundle
import androidx.fragment.app.FragmentActivity
import androidx.fragment.app.Fragment
import androidx.viewpager2.widget.ViewPager2
import com.main.treasurex.R
import androidx.viewpager2.adapter.FragmentStateAdapter



/**
* The number of pages (wizard steps) to show in this demo.
*/
private const val NUM_PAGES = 5

class SlideFragmentActive : FragmentActivity() {

/**
* The pager widget, which handles animation and allows swiping horizontally to access previous
* and next wizard steps.
*/
private lateinit var mPager: ViewPager2

override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.fragment_sample)

// Instantiate a ViewPager and a PagerAdapter.
mPager = findViewById(R.id.pager)

// The pager adapter, which provides the pages to the view pager widget.
val pagerAdapter = ScreenSlidePagerAdapter(this)
mPager.adapter = pagerAdapter
}

override fun onBackPressed() {
if (mPager.currentItem == 0) {
// If the user is currently looking at the first step, allow the system to handle the
// Back button. This calls finish() on this activity and pops the back stack.
super.onBackPressed()
} else {
// Otherwise, select the previous step.
mPager.currentItem = mPager.currentItem - 1
}
}

/**
* A simple pager adapter that represents 5 ScreenSlidePageFragment objects, in
* sequence.
*/
private inner class ScreenSlidePagerAdapter(fa: FragmentActivity) : FragmentStateAdapter(fa) {

override fun getItemCount(): Int = NUM_PAGES

override fun getItem(position: Int): Fragment = SlideFragment()
}
}


依赖关系是

dependencies {
//noinspection GradleCompatible
implementation "androidx.viewpager2:viewpager2:1.0.0-beta04"

implementation fileTree(dir: 'libs', include: ['*.jar'])
implementation"org.jetbrains.kotlin:kotlin-stdlib-jdk7:$kotlin_version"
implementation 'androidx.appcompat:appcompat:1.0.2'
implementation 'androidx.core:core-ktx:1.0.2'
implementation 'com.google.android.material:material:1.0.0'
implementation 'androidx.constraintlayout:constraintlayout:1.1.3'
implementation 'androidx.navigation:navigation-fragment:2.0.0'
implementation 'androidx.navigation:navigation-ui:2.0.0'
implementation 'androidx.lifecycle:lifecycle-extensions:2.0.0'
implementation 'androidx.navigation:navigation-fragment-ktx:2.0.0'
implementation 'androidx.navigation:navigation-ui-ktx:2.0.0'
testImplementation 'junit:junit:4.12'
androidTestImplementation 'androidx.test:runner:1.1.1'
androidTestImplementation 'androidx.test.espresso:espresso-core:3.1.1'

}

感谢您的所有帮助!!!!!!!急诊室

最佳答案

/**
* A simple pager adapter that represents 5 ScreenSlidePageFragment objects, in
* sequence.
*/
private inner class ScreenSlidePagerAdapter(fa: FragmentActivity) : FragmentStateAdapter(fa) {

override fun createFragment(position: Int): Fragment {
return ScreenSlidePageFragment()
}

override fun getItemCount(): Int = NUM_PAGES

override fun getItem(position: Int): Fragment = SlideFragment()
}

关于java - Kotlin ViewPager2 : Class 'ScreenSlidePagerAdapter' is not abstract and does not implement base class member,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58155132/

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