gpt4 book ai didi

java - Spring Data JPA 投影从数据库中选择的字段

转载 作者:行者123 更新时间:2023-12-02 00:04:13 26 4
gpt4 key购买 nike

我正在测试 Spring Data 1.10.4.RELEASE,遵循 Spring Data Docs http://docs.spring.io/spring-data/jpa/docs/current/reference/html/#projections 中的示例

我注意到一些问题,我有两个问题。

首先假设我有这两个实体:

@Entity
public class Person {

@Id @GeneratedValue
private Long id;
private String firstName, lastName;

@OneToOne
private Address address;
}

@Entity
public class Address {

@Id @GeneratedValue
private Long id;
private String street, state, country;
}
  • 问题 1:

对于以下预测:

interface PersonLimited {  

String getFirstName();

AddressLimited getAddress();
}

interface AddressLimited {

String getCountry();
}

当我运行findPersonByFirstNameProjectedForLimitedData

interface PersonRepository extends CrudRepository<Person, Long> {

@Query("select p from Person p where p.firstName = ?1")
PersonLimited findPersonByFirstNameProjectedForLimitedData(String firstName);
}

它返回的正是预期的结果:

{
firstName: 'Homer',
address: {
country: 'USA'
}
}

现在,如果我查看生成的 SQL,这就是我所得到的:

SELECT person0_.firstName      AS col_0_0_, 
address1_.id AS id1_13_,
address1_.street AS street2_13_,
address1_.state AS state3_13_,
address1_.country AS country4_13_
FROM person person0_
LEFT OUTER JOIN address address1_
ON person0_.addressId = address1_.id
WHERE person0_.firstName = ?

“Person”实体的投影仅选择“fistName”,这是 100% 正确的,因为在 PersonLimited 接口(interface)中我只定义了“getFirstName”。

但是对于“Address”实体,它会选择所有字段,这是错误的,因为在 AddressLimited 接口(interface)中我只定义了“getCountry”,它应该只选择“country”。

生成的查询应该类似于:

SELECT person0_.firstName      AS col_0_0_, 
address1_.country AS country4_13_
FROM person person0_
LEFT OUTER JOIN address address1_
ON person0_.addressId = address1_.id
WHERE person0_.firstName = ?

所以问题是,为什么它不只为地址“实体”选择“国家/地区”字段?为什么需要选择所有字段?这是 Spring 的一个错误吗?

  • 问题 2:

对于与上面相同的投影,

当我运行findAllPersonsProjectedForLimitedData

interface PersonRepository extends CrudRepository<Person, Long> {

@Query("select p from Person p")
List<PersonLimited> findAllPersonsProjectedForLimitedData();
}

它返回的正是预期的结果:

[
{
firstName: 'Homer',
address: {
country: 'USA'
}
},
{
firstName: 'Maggie',
address: {
country: 'USA'
}
}
]

现在,如果我查看生成的 SQL,这就是我所得到的:

SELECT person0_.id                 AS id1_18_, 
person0_.firstName AS firstName2_18_,
person0_.lastName AS lastName3_18_,
person0_.addressid AS company4_18_
FROM person person0_

SELECT address0_.id AS id1_13_0_,
address0_.street AS street2_13_0_,
address0_.state AS state3_13_0_,
address0_.country AS country4_13_0_
FROM address address0_
WHERE address0_.id = ?

这里,Person 和 Address 实体的投影选择了所有错误的字段,它应该只选择“firstName”和“country”。

生成的查询应该类似于:

SELECT person0_.firstName        AS firstName2_18_
FROM person person0_

SELECT address0_.country AS country4_13_0_
FROM address address0_
WHERE address0_.id = ?

这是正常行为吗,不应该只选择我们需要的字段吗?

谢谢

最佳答案

如果您想将注释@Query与Spring Data Projections一起使用,您必须使用字段别名,并且需要确保为与投影字段匹配的项目添加别名。以下代码应该适用于问题 1:

interface PersonRepository extends CrudRepository<Person, Long> {

@Query("select p.firstName as firstname, p.address as address from Person p where p.firstName = ?1")
PersonLimited findPersonByFirstNameProjectedForLimitedData(String firstName);
}

您可以使用的另一种选择是使用 Property Expressions 定义您的查询。 。只要有可能:

interface PersonRepository extends CrudRepository<Person, Long> {

List<PersonLimited> findByFirstName(String firstName);
}

关于java - Spring Data JPA 投影从数据库中选择的字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58165138/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com