oracle - Oracle 触发器中的行编号如何工作？

Question

我有一个引发错误的触发器，但我不确定如何知道哪一行 PL/SQL 代码引发了该错误。我的错误是

[Oracle]ORA-01403: no data found ORA-06512: at "MYSCHEMA.FOO_BI", line 9

我的触发器是这样的:

create or replace TRIGGER "MYSCHEMA"."FOO_BI" 
BEFORE INSERT ON FOO REFERENCING OLD AS OLD NEW AS NEW FOR EACH ROW
DECLARE
 NUM1 NUMBER;
 NUM2 NUMBER;

BEGIN

     -- some comment
  if :new.batch_num is null then
   SELECT COUNT(*) INTO :NEW.BATCH_NUM FROM FOO WHERE CORP_ID = :NEW.CORP_ID;
  end if;

  if :new.batch_id is null or :new.batch_id = '' then
    :NEW.BATCH_ID := :NEW.CORP_ID || '-' || :NEW.BATCH_NUM;
  end if;

/* etc... */     

我发现了类似 similar question 的内容但行编号以创建或替换...开头，并将我的错误行表示为注释，我认为这一定是假的。触发器执行中抛出错误时如何报告行号？

Answer 1

行编号(如堆栈跟踪中所报告)从第 1 行的 DECLARE 开始。因此，如果执行以下操作:

CREATE OR REPLACE TRIGGER foo
BEFORE INSERT ON test1 
REFERENCING OLD AS OLD NEW AS NEW 
FOR EACH ROW
DECLARE
n1 NUMBER := 1;
n2 NUMBER := 2;

BEGIN

  -- a comment
  IF :new.n1 IS NULL THEN
    n1 := n2/0;
  END IF;
END;
/

SQL> insert into test1 values (3,'XX','YY',NULL);

insert into test1 values (3,'XX','YY',NULL)

ORA-01476: divisor is equal to zero
ORA-06512: at "XXX.FOO", line 9
ORA-04088: error during execution of trigger 'XXX.FOO'

SQL> select line, text from all_source where name = 'FOO';

      LINE TEXT
---------- --------------------------------------------------------------------------------
         1 TRIGGER foo
         2 BEFORE INSERT ON test1
         3 REFERENCING OLD AS OLD NEW AS NEW
         4 FOR EACH ROW
         5 DECLARE
         6 n1 NUMBER := 1;
         7 n2 NUMBER := 2;
         8 
         9 BEGIN
        10 
        11   -- a comment
        12   IF :new.n1 IS NULL THEN
        13     n1 := n2/0;
        14   END IF;
        15 END;

15 rows selected

您可以看到错误报告为发生在第 9 行，实际上是源代码中的第 13 行。