java - java 获取 int 数字从零到九一一一

Question

您好，我想知道从 txt 文件扫描 int 数字的最佳和最简单的方法一个又一个的数字我能找到的数字是0到9除此以外例如:

24351235312531135

我想每次扫描这些输入时得到

2 
4
3
5
1
2

编辑:

My input in txt file is something like this
 13241235135135135
 15635613513513531
 13513513513513513
 13251351351351353
 13245135135135315
 13513513513513531

6 行，位数已知 ....我找到了这段代码，但不起作用

import java.util.Scanner;


public class ScannerReadFile {

public static void main(String[] args) {

    // Location of file to read
    File file = new File("data.txt");

    try {

        Scanner scanner = new Scanner(file);

        while (scanner.hasNextLine()) {
            String line = scanner.nextLine();
            System.out.println(line);
        }
        scanner.close();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

}

}

我无法找到我面临的确切查询

Answer 1

试试这个:

public static void main(String[] args) {
    File file = new File("data.txt");
    try {

        Scanner scanner = new Scanner(file);

        while (scanner.hasNextLine()) {
            String line = scanner.nextLine();
            for (int i = 0; i < line.length(); i++) {
                System.out.println(line.charAt(i));
            }
        }
        scanner.close();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

}