Java 解码 JSON

Question

我正在尝试将 json 字符串解码为 Map。

我知道有很多这样的问题，但我需要非常具体的格式。例如，我有 json 字符串:

{
    "map": {
        "a": "b",
        "c": "d",
    },
    "map2": {
        "aa": "bb",
        "cc": "dd",
    },
    "something": "a",
    "something2": "b"
}

我需要得到如下结果:

"map.a" => "b"
"map.c" => "d"
"map2.aa" => "bb"
"map2.cc" => "dd"
"something" => "a"
"something2" => "b"

我确定按键不会包含任何点。我查看了一些 JSON 库，但我不需要那么多函数，只需解码并存储在 Java 映射中即可。如果没有简单的方法，我会为此编写自己的算法，我希望它不会那么难......

感谢您的帮助。

Answer 1

我使用了org.codehaus.jackson。执行以下操作:

    HashMap<String, Object> content = null;
    HashMap<String, String> result = new HashMap<String, String>();

    try {
        JsonFactory factory = new JsonFactory();
        ObjectMapper mapper = new ObjectMapper(factory);
        TypeReference<HashMap<String, Object>> typeRef = new TypeReference<HashMap<String, Object>>() {
        };
        content = mapper.readValue(jsonString, typeRef);

    } catch (Exception ex) {
        System.out.println("Exception : " + ex);
    } 
    // now content has everything inside
    for(String s : content.keySet()){
        Object obj = content.get(s);
        if(obj instanceof String){
            result.put(s, (String)obj);
        } else {
            HashMap<String,String> hm = (HashMap<String,String>)obj;
            for(String s2: hm.keySet()){
                result.put(s+"."+s2, hm.get(s2));
            }

        }
    }

编辑:已测试且正在运行