regex - 正面回顾后跟逗号分隔列表

Question

我想看看是否有办法在积极回顾后为每个逗号分隔列表获取匹配组。

例如

#summertime swimming, running, tanning

正则表达式(到目前为止)

(?<=#summertime\s)(.+)

返回

["swimming, running, tanning"]

期望的结果

["swimming", "running", "tanning"]

Answer 1

在 php 中你可以通过 PCRE 动词 (*SKIP)(*F),

(?:^(?:(?!#summertime).)*$|^.*?#summertime)(*SKIP)(*F)|\w+

DEMO